Eloquent 加入 table 日期
Eloquent join table on date
点击次数 table 架构:
user_id as (integer)
created_at as (Y-m-d H:i:s)
观看次数table
user_id as (integer)
created_at as (Y-m-d H:i:s)
我需要按日期而非日期时间对第一个 table + 第二个 table 中的记录进行计数:
现在我正在使用 2 个查询:
$clicks = $user->clicks()
->select(\DB::raw("DATE_FORMAT(created_at, '%d/%m/%Y') as date"),
\DB::raw("COUNT(*) as clicks"))
->groupBy('date')
->orderBy('date', 'ASC')
->get()->toArray();
$views = $user->views()
->select(\DB::raw("DATE_FORMAT(created_at, '%d/%m/%Y') as date"),
\DB::raw("COUNT(*) as views"))
->groupBy('date')
->orderBy('date', 'ASC')
->get()->toArray();
在我有一个循环之后
$out = [];
for ($i=0; $i < count($views); $i++) {
$out[] = [
'date' => $views[$i]['date'],
'clicks' => $clicks[$i]['clicks'],
'views' => $views[$i]['views']
];
}
但是如果点击存在并且在某个日期没有查看它不会将其添加到数组中
可以按日期格式加入 created_at 吗?没有时间?
因为 MySQL 不支持完全加入试试这个
select date(clicks.created_at)as 'Date',
count(clicks.user_id) as 'clicks',
count(views.user_id)as 'views'
from clicks
left join views on date(views.created_at)=date(clicks.created_at)
group by date(clicks.created_at)
union
select date(views.created_at)as 'Date',
count(clicks.user_id) as 'clicks',
count(views.user_id)as 'views'
from views
left join clicks on date(views.created_at)=date(clicks.created_at)
group by date(views.created_at)
因为您的查询中包含计数,请尝试此查询
select a.Date,a.clicks,b.views
from(select date(clicks.created_at)as 'Date',
count(clicks.user_id) as 'clicks'
from clicks
group by date(clicks.created_at))a
left join (select date(views.created_at)as 'Date',
count(views.user_id) as 'views'
from views
group by date(views.created_at))b
on a.date=b.date
union
select a.Date,b.clicks,a.views
from(select date(views.created_at)as 'Date',
count(views.user_id) as 'views'
from views
group by date(views.created_at))a
left join (select date(clicks.created_at)as 'Date',
count(clicks.user_id) as 'clicks'
from clicks
group by date(clicks.created_at))b
on a.date=b.date
点击次数 table 架构:
user_id as (integer)
created_at as (Y-m-d H:i:s)
观看次数table
user_id as (integer)
created_at as (Y-m-d H:i:s)
我需要按日期而非日期时间对第一个 table + 第二个 table 中的记录进行计数:
现在我正在使用 2 个查询:
$clicks = $user->clicks()
->select(\DB::raw("DATE_FORMAT(created_at, '%d/%m/%Y') as date"),
\DB::raw("COUNT(*) as clicks"))
->groupBy('date')
->orderBy('date', 'ASC')
->get()->toArray();
$views = $user->views()
->select(\DB::raw("DATE_FORMAT(created_at, '%d/%m/%Y') as date"),
\DB::raw("COUNT(*) as views"))
->groupBy('date')
->orderBy('date', 'ASC')
->get()->toArray();
在我有一个循环之后
$out = [];
for ($i=0; $i < count($views); $i++) {
$out[] = [
'date' => $views[$i]['date'],
'clicks' => $clicks[$i]['clicks'],
'views' => $views[$i]['views']
];
}
但是如果点击存在并且在某个日期没有查看它不会将其添加到数组中 可以按日期格式加入 created_at 吗?没有时间?
因为 MySQL 不支持完全加入试试这个
select date(clicks.created_at)as 'Date',
count(clicks.user_id) as 'clicks',
count(views.user_id)as 'views'
from clicks
left join views on date(views.created_at)=date(clicks.created_at)
group by date(clicks.created_at)
union
select date(views.created_at)as 'Date',
count(clicks.user_id) as 'clicks',
count(views.user_id)as 'views'
from views
left join clicks on date(views.created_at)=date(clicks.created_at)
group by date(views.created_at)
因为您的查询中包含计数,请尝试此查询
select a.Date,a.clicks,b.views
from(select date(clicks.created_at)as 'Date',
count(clicks.user_id) as 'clicks'
from clicks
group by date(clicks.created_at))a
left join (select date(views.created_at)as 'Date',
count(views.user_id) as 'views'
from views
group by date(views.created_at))b
on a.date=b.date
union
select a.Date,b.clicks,a.views
from(select date(views.created_at)as 'Date',
count(views.user_id) as 'views'
from views
group by date(views.created_at))a
left join (select date(clicks.created_at)as 'Date',
count(clicks.user_id) as 'clicks'
from clicks
group by date(clicks.created_at))b
on a.date=b.date