如何编写单个 SQL 查询以获取 SQL Server 2008 中其他列的列聚合？

Question

我有一个 table Employee.

如何获取 table 的聚合列作为单独的列，如图所示？

Answer 1

我去年遇到的确切问题。希望对您有所帮助。

SELECT e1.EmpId,
       e1.EmpName
       e1.EmpSalary,
       SUM(e2.EmpSalary) AS Aggregate_Salary 
FROM Employee e1 JOIN Employee e2 
ON e1.id >= e2.id GROUP BY e1.EmpId,
   e1.EmpName,
   e1.EmpSalary

Answer 2

使用相关子查询：

select EmpId, EmpName, EmpSalary, (select sum(EmpSalary) from Employee e2
                                   where e2.EmpId <= e1.EmpId) as AggregateSalary
from Employee e1

Answer 3

您没有指定您的 DBMS，所以这是 ANSI SQL:

select empid, 
       empname,
       empsalary,
       sum(empsalary) over (order by empid) as aggregate_salary
from employee
order by empid;

如何编写单个 SQL 查询以获取 SQL Server 2008 中其他列的列聚合？

How to write a single SQL query to get aggregate of column as other column in SQL Server 2008?

sql

sql-server

sql-server-2008

cumulative-sum