将对象添加到队列后访问对象变量？

Question

我正在尝试了解如何获取已添加到队列中的客户对象名称和食物？所以说我想在第一个客户对象添加到队列后使用其名称和食物元素打印一个字符串？队列查看方法是占位符，因为我不确定在将对象添加到队列后如何访问对象的名称和食物。如果我打印 peek 方法，它只会给我内存位置，而不是对象的食物或名称。

结果会是这样的：

“您想加工什么：披萨还是沙拉？

沙拉

詹姆斯的沙拉做好了！”

代码：

主要class:

import java.util.Scanner;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.LinkedList;
import java.util.Queue;

public class Main {

    public static void main(String[] args) throws FileNotFoundException {
        File customerTxt = new File("customer.txt");
        Queue<Customer> pizza = new LinkedList<Customer>();
        Queue<Customer> salad = new LinkedList<Customer>();
        try {
            Scanner readCus = new Scanner(customerTxt);
            Scanner readFood = new Scanner(System.in);
            while (readCus.hasNextLine()) {
                String line = readCus.nextLine();
                String[] strArray = line.split(",");
                String customerName = strArray[0];
                String customerFood = strArray[1];
                Customer cus = new Customer(customerName, customerFood);
                if (customerFood.equalsIgnoreCase("salad")) {
                    salad.add(cus);
                }
                if (customerFood.equalsIgnoreCase("pizza")) {
                    pizza.add(cus);
                }
            }
            if (pizza.isEmpty() == false && salad.isEmpty() == false) {
                System.out.println("What kind of food would you like to make?");
                String foodChoice = readFood.nextLine();
                if (foodChoice.equalsIgnoreCase("salad")) {
                    System.out.println(salad.peek());
                }
                if (foodChoice.equalsIgnoreCase("pizza")) {
                    System.out.println(salad.peek());
                }
            }
            if (pizza.isEmpty() == true && salad.isEmpty() == false) {
                System.out.println("There are no Pizzas left to process. I will just finish the rest of the Salads");
                while (salad.isEmpty() == false) {
                    System.out.println(salad.peek());
                }
            }
            if (pizza.isEmpty() == false && salad.isEmpty() == true) {
                System.out.println("There are no Salads left to process. I will just finish the rest of the Pizzas");
                while (pizza.isEmpty() == false) {
                    System.out.println(pizza.peek());
                }
            }
        }

        catch (FileNotFoundException e) {
            e.printStackTrace();
        }
    }
}

客户Class：

public class Customer {

    public String name = "";

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String food = "";

    public String getFood() {
        return food;
    }

    public void setFood(String food) {
        this.food = food;
    }

    public Customer(String customerName, String customerFood) {
        this.name = customerName;
        this.food = customerFood;
    }



    }

Answer 1

根据 LinkedList.peek()，它return 是正确的对象。我相信您只是看到了对象的散列，因为您打印了 Customer 对象，该对象尚未重新定义 .toString() ：您正在使用 Object.toString()，其中 return 是您看到的散列。

如果您总是想将您的 Customer 表示为它的名称和食物选择，请按照 Zack Macomber 的建议在 Customer 中重新定义 .toString()，或者选择 System.out.println(queue.peek().getName() + " choosed " + queue.peek().getFood()) 或类似的东西。

将对象添加到队列后访问对象变量？

Access object variables after object added to a queue?

java

oop

queue

linked-list