QSignalSpy 等待和两个信号

Question

我正在尝试为基于 Qt 的项目（Qt 5、C++03）中的 class 编写单元测试。

class Transaction { // This is just a sample class
//..
public signals:
   void succeeded();
   void failed();
}

Transaction* transaction = new Transaction(this);
QSignalSpy spy(transaction, SIGNAL(succeeded()));
transaction->run();
spy.wait(5000); // wait for 5 seconds

我希望我的测试运行更快。如果交易失败，如何在发出信号 failed() 后中断此 wait() 调用？

我在 QSignalSpy 中没有看到任何可用的插槽 class。

我应该改用 QEventLoop 吗？

Answer 1

您可能必须使用循环并在两个信号都未发出时手动调用 QTest::qWait()：

QSignalSpy succeededSpy(transaction, SIGNAL(succeeded()));
QSignalSpy failedSpy(transaction, SIGNAL(failed()));
for (int waitDelay = 5000; waitDelay > 0 && succeededSpy.count() == 0 && failedSpy.count() == 0; waitDelay -= 100) {
    QTest::qWait(100);
}

QCOMPARE(succeededSpy.count(), 1);

Answer 2

QTestEventLoop的解决方案：

QTestEventLoop loop;
QObject::connect(transaction, SIGNAL(succeeded()), &loop, SLOT(exitLoop()));
QObject::connect(transaction, SIGNAL(failed()), &loop, SLOT(exitLoop()));
transaction->run();
loop.enterLoopMSecs(3000);

带有计时器和QEventLoop的解决方案：

Transaction* transaction = new Transaction(this);
QSignalSpy spy(transaction, SIGNAL(succeeded()));  
QEventLoop loop;  
QTimer timer;
QObject::connect(transaction, SIGNAL(succeeded()), &loop, SLOT(quit()));
QObject::connect(transaction, SIGNAL(failed()), &loop, SLOT(quit()));
QObject::connect(&timer, SIGNAL(timeout()), &loop, SLOT(quit()));
timer.start(3000);
loop.exec();
transaction->run();
QCOMPARE(spy.count(), 1);

QSignalSpy 等待和两个信号

QSignalSpy wait and two signals

c++

qt

unit-testing

qt5

signals-slots