根据月份将行转换为列

Question

我有以下输入：

JAN_OLD FEB_OLD MAR_OLD APR_OLD MAY_OLD JUNE_OLD  JAN_NEW FEB_NEW MAR_NEW APR_NEW MAY_NEW JUNE_NEW
10        11       12      13      14       15       20      21      22      23      24      25

想要的结果集如下：

JAN New OLD
FEB 20  10
MAR 21  11
APR 22  12
MAY 23  13
JUN 24  14

有人可以建议如何实现吗？

Answer 1

多个Union All或单个Cross Apply

SELECT months,old,new
FROM   Your_table
       CROSS apply (VALUES(jan_old,jan_new,'Jan'),
                          (FEB_OLD,FEB_new,'Feb'),
                          (MAR_OLD,MAR_new,'Mar'),
                          (APR_OLD,APR_new,'Apr'),
                          (MAY_OLD,MAY_new,'may'),
                          (JUNE_OLD,JUNE_new,'Jun'))
         cs (old, new, months)

如果您不确定编号。列那么你可能必须使用 Dynamic sql

根据月份将行转换为列

Converting Row Into a Column based on Month

sql

sql-server-2008

pivot

unpivot