JSON 解析：从 NSDictionary 中检索数据并将其存储在数组中

Question

{
    Address =     (
                {
            address = "Bengaluru, Karnataka 560008, India";
            "address_id" = 29;
            "address_title" = "";
            "building_name" = "";
            latitude = "23.95579108";
            longitude = "77.64169808";
            "user_id" = 13;
        },
                {
            address = "Bengaluru, Karnataka 560008, India";
            "address_id" = 31;
            "address_title" = "";
            "building_name" = "";
            latitude = "22.95578162";
            longitude = "77.64173089";
            "user_id" = 13;
        },
                {
            address = "Bengaluru, Karnataka 560008, India";
            "address_id" = 37;
            "address_title" = "";
            "building_name" = "";
            latitude = "22.95577373";
            longitude = "77.64173507";
            "user_id" = 13;
        },
                  {
            address = "256, Road Number 19, Wadla Village, Vadala, Mumbai, Maharashtra 400031, India";
            "address_id" = 49;
            "address_title" = dsa;
            "building_name" = das;
            latitude = "19.01761470";
            longitude = "72.85616440";
            "user_id" = 13;
        }
    );
}

我正在尝试从 JSON 词典中检索数据。我需要从 Address 字典中获取 address 中的数据并将其存储在一个数组中。我的阵列应该是这样的： [Bengaluru, Karnataka 560008, India,Bengaluru, Karnataka 560008, India,Bengaluru, Karnataka 560008, India,256, Road Number 19, Wadla Village, Vadala, Mumbai, Maharashtra 400031, India]

需要帮助。

Answer 1

Filtering NSDictionary with predicate

您可以使用 NSPredicate 过滤 NSDictionary。

假设你的字典是 NSDictionary *dict

NSArray *resultArray = [[dict objectForKey:@"Address" allValues] filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(key == %@)", @"address"]];

Answer 2

NSMutableArray *resultArray = [NSMutableArray new];   
NSError *jsonError = [[NSError alloc] init];
NSDictionary *pR = [NSJSONSerialization JSONObjectWithData:yourJsonObject options:NSJSONReadingAllowFragments error:&jsonError];
NSArray *pArray = pR[@"Address"];

for(NSDictionary *dict in pR)
{
    [resultArray addObject:dict[@"address"]];
}

JSON 解析：从 NSDictionary 中检索数据并将其存储在数组中

JSON Parsing : Retrieving data from the NSDictionary and storing it in an array

parsing

json

nsdictionary

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