如何在 Javascript/Jquery 中更改此 css 伪按钮
How to I change this css psuedo button in Javascript/Jquery
我发现这个非常好的复选框按钮样式(下面的 link)并且一直在尝试使用 jQuery 来打开和关闭它。我以前没有用过很多伪class,一般我只是加一个'active' class.
https://proto.io/freebies/onoff/
我需要根据服务器响应在页面加载时打开或关闭按钮,但我似乎无法在不破坏它的情况下操作 CSS。 activate/deactivate 这个按钮是什么意思?
.onoffswitch {
position: relative;
width: 90px;
-webkit-user-select: none;
-moz-user-select: none;
-ms-user-select: none;
}
.onoffswitch-checkbox {
display: none;
}
.onoffswitch-label {
display: block;
overflow: hidden;
cursor: pointer;
border: 2px solid #999999;
border-radius: 20px;
}
.onoffswitch-inner {
display: block;
width: 200%;
margin-left: -100%;
transition: margin 0.3s ease-in 0s;
}
.onoffswitch-inner:before,
.onoffswitch-inner:after {
display: block;
float: left;
width: 50%;
height: 30px;
padding: 0;
line-height: 30px;
font-size: 14px;
color: white;
font-family: Trebuchet, Arial, sans-serif;
font-weight: bold;
box-sizing: border-box;
}
.onoffswitch-inner:before {
content: "ON";
padding-left: 10px;
background-color: #34A7C1;
color: #FFFFFF;
}
.onoffswitch-inner:after {
content: "OFF";
padding-right: 10px;
background-color: #EEEEEE;
color: #999999;
text-align: right;
}
.onoffswitch-switch {
display: block;
width: 18px;
margin: 6px;
background: #FFFFFF;
position: absolute;
top: 0;
bottom: 0;
right: 56px;
border: 2px solid #999999;
border-radius: 20px;
transition: all 0.3s ease-in 0s;
}
.onoffswitch-checkbox:checked + .onoffswitch-label .onoffswitch-inner {
margin-left: 0;
}
.onoffswitch-checkbox:checked + .onoffswitch-label .onoffswitch-switch {
right: 0px;
}
<div class="onoffswitch">
<input type="checkbox" name="onoffswitch" class="onoffswitch-checkbox" id="myonoffswitch" checked>
<label class="onoffswitch-label" for="myonoffswitch">
<span class="onoffswitch-inner"></span>
<span class="onoffswitch-switch"></span>
</label>
</div>
您不能使用 javascript 删除 :before
或 :after
选择器,因为这些是您制定的 CSS 规则。
相反,根据需要创建两个单独的 类:
.start-state:before {
...
}
.end-state:before {
...
}
然后将您的 javascript 更改为:
$(document).ready(function()
{
$('.onoffswitch-inner').addClass('end-state').removeClass('start-state');
}
或者,您可以将默认 :before
状态添加到 .onoffswitch-inner
CSS 规则,然后通过添加 覆盖它 .onoffswitch-inner.active:before
规则。
这会让你做到$('.onoffswitch-inner').toggleClass('active');
。
您想要以编程方式更改状态,请不要 fiddle 与 CSS 类、
使用jQuery只是一个单行本:
$('#myonoffswitch').attr('checked', false); // turn off
$('#myonoffswitch').attr('checked', true); // turn on
我发现这个非常好的复选框按钮样式(下面的 link)并且一直在尝试使用 jQuery 来打开和关闭它。我以前没有用过很多伪class,一般我只是加一个'active' class.
https://proto.io/freebies/onoff/
我需要根据服务器响应在页面加载时打开或关闭按钮,但我似乎无法在不破坏它的情况下操作 CSS。 activate/deactivate 这个按钮是什么意思?
.onoffswitch {
position: relative;
width: 90px;
-webkit-user-select: none;
-moz-user-select: none;
-ms-user-select: none;
}
.onoffswitch-checkbox {
display: none;
}
.onoffswitch-label {
display: block;
overflow: hidden;
cursor: pointer;
border: 2px solid #999999;
border-radius: 20px;
}
.onoffswitch-inner {
display: block;
width: 200%;
margin-left: -100%;
transition: margin 0.3s ease-in 0s;
}
.onoffswitch-inner:before,
.onoffswitch-inner:after {
display: block;
float: left;
width: 50%;
height: 30px;
padding: 0;
line-height: 30px;
font-size: 14px;
color: white;
font-family: Trebuchet, Arial, sans-serif;
font-weight: bold;
box-sizing: border-box;
}
.onoffswitch-inner:before {
content: "ON";
padding-left: 10px;
background-color: #34A7C1;
color: #FFFFFF;
}
.onoffswitch-inner:after {
content: "OFF";
padding-right: 10px;
background-color: #EEEEEE;
color: #999999;
text-align: right;
}
.onoffswitch-switch {
display: block;
width: 18px;
margin: 6px;
background: #FFFFFF;
position: absolute;
top: 0;
bottom: 0;
right: 56px;
border: 2px solid #999999;
border-radius: 20px;
transition: all 0.3s ease-in 0s;
}
.onoffswitch-checkbox:checked + .onoffswitch-label .onoffswitch-inner {
margin-left: 0;
}
.onoffswitch-checkbox:checked + .onoffswitch-label .onoffswitch-switch {
right: 0px;
}
<div class="onoffswitch">
<input type="checkbox" name="onoffswitch" class="onoffswitch-checkbox" id="myonoffswitch" checked>
<label class="onoffswitch-label" for="myonoffswitch">
<span class="onoffswitch-inner"></span>
<span class="onoffswitch-switch"></span>
</label>
</div>
您不能使用 javascript 删除 :before
或 :after
选择器,因为这些是您制定的 CSS 规则。
相反,根据需要创建两个单独的 类:
.start-state:before {
...
}
.end-state:before {
...
}
然后将您的 javascript 更改为:
$(document).ready(function()
{
$('.onoffswitch-inner').addClass('end-state').removeClass('start-state');
}
或者,您可以将默认 :before
状态添加到 .onoffswitch-inner
CSS 规则,然后通过添加 覆盖它 .onoffswitch-inner.active:before
规则。
这会让你做到$('.onoffswitch-inner').toggleClass('active');
。
您想要以编程方式更改状态,请不要 fiddle 与 CSS 类、
使用jQuery只是一个单行本:
$('#myonoffswitch').attr('checked', false); // turn off
$('#myonoffswitch').attr('checked', true); // turn on