在正则表达式 reg_split 中使用 splitAt 将它们存储在结果数组中

Question

有没有办法在正则表达式 preg_split 中使用 splitAt，并将它们与结果一起存储在结果数组中？例如：

$text = " did the great white eat the fishes ";
$text = preg_split("~( did | eat )~", $text, -1, PREG_SPLIT_NO_EMPTY); 

print_r($text);

结果：

Array ( [0] => the great white [1] => the fishes )

想要的结果：

Array ( [0] => the great white [1] => eat [2] => the fishes )

Answer 1

您可以使用 PREG_SPLIT_DELIM_CAPTURE 标志来捕获结果数组中使用的分隔符：

$text = " did the great white eat the fishes ";
$wrds='did|eat';

$arr = preg_split("~\h+($wrds)\h+~", preg_replace("/^\h*($wrds)\h+/", "" $text),
                  -1, PREG_SPLIT_DELIM_CAPTURE));
print_r($arr);

否则：

$arr = preg_split("~^\h+(?:$wrds)\h+|\h+($wrds)\h+~", $text, -1,
              PREG_SPLIT_DELIM_CAPTURE|PREG_SPLIT_NO_EMPTY);

输出：

Array
(
   [0] => the great white
   [1] => eat
   [2] => the fishes
)

Answer 2

如果您只想捕获 'did' 或 'eat' 分隔符
中间，您可能必须先检查边缘情况：

^(?: did | eat )|(?: did | eat )$|( did | eat )

使用这些选项 PREG_SPLIT_DELIM_CAPTURE|PREG_SPLIT_NO_EMPTY

在 Perl 中没有可比的 PREG_SPLIT_NO_EMPTY。

Answer 3

$text = " did the great white eat the fishes ";
$array = preg_split("~( did | eat )~", $text, -1, PREG_SPLIT_NO_EMPTY); 
preg_match("~$array[0](.+?)$array[1]~", $text, $match);

$text1 = $array[0];
$text2 = $array[1];
$text3 = $match[1];

echo $text1."<br>".$text3."<br>".$text2;

结果：

the great white
eat 
the fishes

在正则表达式 reg_split 中使用 splitAt 将它们存储在结果数组中

Using the splitAt in a regex reg_split to store them in the resulting array

php

regex

preg-split