Obj-C 将秒数解析为 dd:hh:mm:ss

Question

我正在计算两个日期之间的差异。我已经创建了自己的解决方案：

NSDate *actualDate = [NSDate date];
NSTimeInterval sec = [eveDate timeIntervalSinceDate:actualDate];
int secondsBetween = sec;
int minBetween     = sec / 60;
int hoursBetween   = sec / 3600;
int daysBetween    = sec / 86400;

_lblDays.text  = [NSString stringWithFormat:@"%d", daysBetween];
_lblHours.text = [NSString stringWithFormat:@"%d", hoursBetween % 24];
_lblMin.text   = [NSString stringWithFormat:@"%d", minBetween % hoursBetween];
_lblSec.text   = [NSString stringWithFormat:@"%d", secondsBetween % minBetween];

但我相信对此有更好的解决方案（例如本机 class），但我找不到任何东西。你能告诉我怎么做更好吗？

Answer 1

这是另一种计算方式。

NSDateComponents *components = [[NSCalendar currentCalendar] components: NSCalendarUnitDay|NSCalendarUnitHour|NSCalendarUnitMinute|NSCalendarUnitSecond
                                                 fromDate: startDate toDate: endDate options: 0];
NSInteger days = [components day];
NSInteger hour=[components hour];
NSInteger minutes=[components minute];
NSInteger sec = [components second];

Answer 2

您可以使用 NSCalendar and NSDateComponents class 来执行此操作：

NSCalendar *calendar         = [NSCalendar currentCalendar];
NSDateComponents *components = [calendar components:NSCalendarUnitDay|NSCalendarUnitHour|NSCalendarUnitMinute|NSCalendarUnitSecond fromDate:actualDate toDate:eveDate options:0];
NSLog(@"Days->%d Hour->%d, Minute->%d, Second->%d", components.day, components.hour, components.minute, components.second);

Obj-C 将秒数解析为 dd:hh:mm:ss

Obj-C parse seconds to dd:hh:mm:ss

ios

objective-c

date

nsdate

intervals