如何执行区分大小写的嵌套 REPLACE 命令？

Question

我有一个 table:

Building                                        Building
1__bEast                                        1 East
1__bSouth                                       1 South
500__bBldg__d                                   500 Bldg.
501__bBldg__d                                   501 Bldg.
B__u1                                           B-1
B__u2                                           B-2
B__u2__bWest                                    B-2 West
Building__b10__b__PBldg__bTen__p                Building 10 (Bldg Ten)
D__7T__b__PDiagnostic__b__7__bTreatment__p      D & T (Diagnostic & Treatment)
n__fa                                           n/a

左边的列表显示实际table。右边的列表是我希望它们出现在结果中的方式。为了做到这一点，我使用了以下嵌套的 REPLACE 命令：

REPLACE(
    REPLACE(
        REPLACE(
            REPLACE(
                REPLACE(
                    REPLACE(Building,'__P','(')
                ,'__p',')')
            ,'__b',' ')
        ,'__u','-')
    ,'__7','&')
,'__d','.') as [Building]

这个问题是“__P”和“__p”被同等对待，结果是这样的：

Building 10 (Bldg Ten(
D & T (Diagnostic & Treatment(

右括号“)”没有出现。

我尝试使用：

...REPLACE(REPLACE(Building COLLATE SQL_Latin1_General_CP1_CI_AS,'__P','('),'__p',')')...

但它似乎在嵌套的 REPLACE 查询中不起作用。我得到的结果基本相同。

有办法吗？

Answer 1

使用COLLATE SQL_Latin1_General_CP1_CS_AS（区分大小写）：

CREATE TABLE #tab(Building VARCHAR(100));

INSERT INTO #tab
SELECT '1__bEast'                                     
UNION ALL SELECT '1__bSouth'                                       
UNION ALL SELECT '500__bBldg__d'                                  
UNION ALL SELECT '501__bBldg__d'                                   
UNION ALL SELECT 'B__u1'                                           
UNION ALL SELECT 'B__u2'                                           
UNION ALL SELECT 'B__u2__bWest'                                    
UNION ALL SELECT 'Building__b10__b__PBldg__bTen__p'              
UNION ALL SELECT 'D__7T__b__PDiagnostic__b__7__bTreatment__p'      
UNION ALL SELECT 'n__fa';

SELECT Building,
REPLACE(
    REPLACE(
        REPLACE(
            REPLACE(
                REPLACE(
                    REPLACE(Building COLLATE SQL_Latin1_General_CP1_CS_AS ,'__P','(')
                ,'__p',')')
            ,'__b',' ')
        ,'__u','-')
    ,'__7','&')
,'__d','.') as [Building] 
FROM #tab

LiveDemo

输出：

╔════════════════════════════════════════════╦══════════════════════════════╗
║                  Buidling                  ║           Replaced           ║
╠════════════════════════════════════════════╬══════════════════════════════╣
║ 1__bEast                                   ║ 1 East                       ║
║ 1__bSouth                                  ║ 1 South                      ║
║ 500__bBldg__d                              ║ 500 Bldg.                    ║
║ 501__bBldg__d                              ║ 501 Bldg.                    ║
║ B__u1                                      ║ B-1                          ║
║ B__u2                                      ║ B-2                          ║
║ B__u2__bWest                               ║ B-2 West                     ║
║ Building__b10__b__PBldg__bTen__p           ║ Building 10 (Bldg Ten)       ║
║ D__7T__b__PDiagnostic__b__7__bTreatment__p ║ D&T (Diagnostic & Treatment) ║
║ n__fa                                      ║ n__fa                        ║
╚════════════════════════════════════════════╩══════════════════════════════╝

根据您的需要再添加一个 REPLACE(..., 'n__fa', 'n/a') 或 REPLACE(..., '__f', '/')。

如何执行区分大小写的嵌套 REPLACE 命令？

How do you perform a CASE SENSITIVE nested REPLACE command?

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replace

nested

case-sensitive