有没有办法“通过列表进行管道传输”?
Is there a way to `pipe through a list'?
ggplot2
包中一个我从未真正充分利用过的非常酷的功能是向图中添加图层列表。有趣的是,我可以将图层列表作为参数传递给函数,并将它们添加到绘图中。然后我可以获得所需的情节外观,而不必从函数返回情节(这是否是个好主意是另一回事,但这是可能的)。
library(ggplot2)
x <- ggplot(mtcars,
aes(x = qsec,
y = mpg))
layers <- list(geom_point(),
geom_line(),
xlab("Quarter Mile Time"),
ylab("Fuel Efficiency"))
x + layers
有没有办法用管道做到这一点?类似于:
#* Obviously isn't going to work
library(dplyr)
action <- list(group_by(am, gear),
summarise(mean = mean(mpg),
sd = sd(mpg)))
mtcars %>% action
要构建一系列 magrittr 步骤,请从 .
开始
action = . %>% group_by(am, gear) %>% summarise(mean = mean(mpg), sd = sd(mpg))
然后就可以按照OP中想象的那样使用了:
mtcars %>% action
像list
一样,我们可以子集来查看每个步骤:
action[[1]]
# function (.)
# group_by(., am, gear)
要查看所有步骤,请使用 functions(action)
或直接输入名称:
action
# Functional sequence with the following components:
#
# 1. group_by(., am, gear)
# 2. summarise(., mean = mean(mpg), sd = sd(mpg))
#
# Use 'functions' to extract the individual functions.
ggplot2
包中一个我从未真正充分利用过的非常酷的功能是向图中添加图层列表。有趣的是,我可以将图层列表作为参数传递给函数,并将它们添加到绘图中。然后我可以获得所需的情节外观,而不必从函数返回情节(这是否是个好主意是另一回事,但这是可能的)。
library(ggplot2)
x <- ggplot(mtcars,
aes(x = qsec,
y = mpg))
layers <- list(geom_point(),
geom_line(),
xlab("Quarter Mile Time"),
ylab("Fuel Efficiency"))
x + layers
有没有办法用管道做到这一点?类似于:
#* Obviously isn't going to work
library(dplyr)
action <- list(group_by(am, gear),
summarise(mean = mean(mpg),
sd = sd(mpg)))
mtcars %>% action
要构建一系列 magrittr 步骤,请从 .
action = . %>% group_by(am, gear) %>% summarise(mean = mean(mpg), sd = sd(mpg))
然后就可以按照OP中想象的那样使用了:
mtcars %>% action
像list
一样,我们可以子集来查看每个步骤:
action[[1]]
# function (.)
# group_by(., am, gear)
要查看所有步骤,请使用 functions(action)
或直接输入名称:
action
# Functional sequence with the following components:
#
# 1. group_by(., am, gear)
# 2. summarise(., mean = mean(mpg), sd = sd(mpg))
#
# Use 'functions' to extract the individual functions.