Python: 如何警告用户列表中的重复值
Python: How to warn user of duplicate value in list
我正在尝试编写一个程序,允许用户输入任意数量的整数。如您所见,他们将用 'lengthList =....' 来决定。我的目标不仅是删除重复的条目,而且还通知用户重复项。我已经设法删除了重复项,但不知道如何通知用户他们的条目已被删除。例如“已输入 28。已从列表中删除。”
感谢
result = "0"
intList = []
LengthList = int(input("Please enter the amount of numbers")
while len(result) < LengthList:
userNumber = input("Please input a number: ")
intList.append(userNumber)
removeDuplicate = set(intList)
result = list(removeDuplicate)
print (result)
尝试:
# Creating the results list
results = list()
# Casting the string input to int()
amount_of_numbers = int(input("Please enter the amount of numbers: "))
# While lenght of results is lower than the provided amount of numbers
while len(results) < amount_of_numbers:
## Casting the string input to int() since we want to store it as an integer and not as a string
userNumber = int(input("Please input a number: "))
## If the input number is not already in results list
if userNumber not in results:
# Appending the input number to results list
results.append(userNumber)
else:
# Printing a message saying that the number already exists in results list
print ("{} has already been entered".format(userNumber))
# Printing results list
print (results)
输出:
➜ python numbers.py
Please enter the amount of numbers: 4
Please input a number: 1
Please input a number: 2
Please input a number: 3
Please input a number: 1
1 has already been entered
Please input a number: 2
2 has already been entered
Please input a number: 3
3 has already been entered
Please input a number: 4
[1, 2, 3, 4]
尝试使用列表存储值并在添加数字之前测试输入的值是否在其中。
下面是我对这个问题的解决方案:
l = []
while True:
userNumber = input("Please input a number: ")
if userNumber not in l:
userNumber = l.append(userNumber)
print(l)
else:
print(f'{userNumber} already exist in the list, and your list is {l}')
输出:
Please input a number: 1
['1']
Please input a number: 1
1 already exist in the list, and your list is ['1']
Please input a number: 2
['1', '2']
Please input a number: 2
2 already exist in the list, and your list is ['1', '2']
Please input a number: 3
我正在尝试编写一个程序,允许用户输入任意数量的整数。如您所见,他们将用 'lengthList =....' 来决定。我的目标不仅是删除重复的条目,而且还通知用户重复项。我已经设法删除了重复项,但不知道如何通知用户他们的条目已被删除。例如“已输入 28。已从列表中删除。”
感谢
result = "0"
intList = []
LengthList = int(input("Please enter the amount of numbers")
while len(result) < LengthList:
userNumber = input("Please input a number: ")
intList.append(userNumber)
removeDuplicate = set(intList)
result = list(removeDuplicate)
print (result)
尝试:
# Creating the results list
results = list()
# Casting the string input to int()
amount_of_numbers = int(input("Please enter the amount of numbers: "))
# While lenght of results is lower than the provided amount of numbers
while len(results) < amount_of_numbers:
## Casting the string input to int() since we want to store it as an integer and not as a string
userNumber = int(input("Please input a number: "))
## If the input number is not already in results list
if userNumber not in results:
# Appending the input number to results list
results.append(userNumber)
else:
# Printing a message saying that the number already exists in results list
print ("{} has already been entered".format(userNumber))
# Printing results list
print (results)
输出:
➜ python numbers.py
Please enter the amount of numbers: 4
Please input a number: 1
Please input a number: 2
Please input a number: 3
Please input a number: 1
1 has already been entered
Please input a number: 2
2 has already been entered
Please input a number: 3
3 has already been entered
Please input a number: 4
[1, 2, 3, 4]
尝试使用列表存储值并在添加数字之前测试输入的值是否在其中。 下面是我对这个问题的解决方案:
l = []
while True:
userNumber = input("Please input a number: ")
if userNumber not in l:
userNumber = l.append(userNumber)
print(l)
else:
print(f'{userNumber} already exist in the list, and your list is {l}')
输出:
Please input a number: 1
['1']
Please input a number: 1
1 already exist in the list, and your list is ['1']
Please input a number: 2
['1', '2']
Please input a number: 2
2 already exist in the list, and your list is ['1', '2']
Please input a number: 3