将复杂对象图序列化为 XML 并返回

Question

问题

我有以下对象图：

AppBundle\Controller\Person Object
(
    [name:AppBundle\Controller\Person:private] => Person Name
    [age:AppBundle\Controller\Person:private] => 10
    [phones:AppBundle\Controller\Person:private] => Array
        (
            [0] => AppBundle\Controller\Telephone Object
                (
                    [phone:AppBundle\Controller\Telephone:private] => 221-16-78
                )
            [1] => AppBundle\Controller\Telephone Object
                (
                    [phone:AppBundle\Controller\Telephone:private] => 221-16-78
                )
        )
)

并使用我的控制器中的以下代码进行序列化：

$s = $this->get("serializer")->serialize($person, 'xml');

这给了我以下结果：

<response>
  <name>Person Name</name>
  <age>10</age>
  <phones>
    <phone>221-16-78</phone>
  </phones>
  <phones>
    <phone>221-16-78</phone>
  </phones>
</response>

反序列化使用如下代码：

$this->get("serializer")->deserialize($s, 'AppBundle\Controller\Person', 'xml');

正在回馈以下内容：

AppBundle\Controller\Person Object
(
    [name:AppBundle\Controller\Person:private] => Person Name
    [age:AppBundle\Controller\Person:private] => 10
    [phones:AppBundle\Controller\Person:private] => Array
        (
            [0] => Array
                (
                    [phone] => 221-16-78
                )
            [1] => Array
                (
                    [phone] => 221-16-78
                )
        )
)

问题

首先，有没有办法接收一个xml如下：

<response>
  <name>Person Name</name>
  <age>10</age>
  <phones>
    <telephone>
      <phone>221-16-78</phone>
    </telephone>
    <telephone>
      <phone>221-16-78</phone>
    </telephone>
  </phones>
</response>

其次，我怎样才能将它反序列化回对象图（人和电话），一旦使用简单的反序列化它 returns 一个对象 person 具有一组电话，它包含一个关联数组而不是 Telephone 个对象。

模型/控制器

这是我的模型/控制器类:

<?php

namespace AppBundle\Controller;

class Person {

    private $name;
    private $age;
    private $phones;

    public function getName() {
        return $this->name;
    }

    public function getAge() {
        return $this->age;
    }

    public function getPhones() {
        return $this->phones;
    }

    public function setName($name) {
        $this->name = $name;
    }

    public function setAge($age) {
        $this->age = $age;
    }

    public function setPhones($phones) {
        $this->phones = $phones;
    }

}

<?php

namespace AppBundle\Controller;

class Telephone {

    private $phone;

    public function getPhone() {
        return $this->phone;
    }

    public function setPhone($phone) {
        $this->phone = $phone;
    }

}

还有我的控制器方法：

/**
 * @Route("/", name="homepage")
 */
public function indexAction(Request $request)
{

    $phone1 = new Telephone();
    $phone1->setPhone("221-16-78");

    $phone2 = new Telephone();
    $phone2->setPhone("221-16-78");

    $person = new Person();
    $person->setName("Person Name");
    $person->setAge(10);
    $person->setPhones(array($phone1, $phone2));

    print_r($person);

    $s = $this->get("serializer")->serialize($person, 'xml');
    $p = $this->get("serializer")->deserialize($s, 'AppBundle\Controller\Person', 'xml');

    print_r($p);

}

使用 JMS 序列化程序的解决方案

我能够通过使用注释（主要是类型和列表详细信息）向序列化程序提供一些提示来解决 JMS 序列化程序的这个问题，如下所示：

<?php

namespace AppBundle\Controller;

use JMS\Serializer\Annotation\Type;
use JMS\Serializer\Annotation\XmlList;

class Person {

    /**
     * @Type("string")
     */
    private $name;
    /**
     * @Type("integer")
     */
    private $age;
    /**
     * @Type("array<AppBundle\Controller\Telephone>")
     * @XmlList(entry = "telephone")
     */
    private $phones;

    public function getName() {
        return $this->name;
    }

    public function getAge() {
        return $this->age;
    }

    public function getPhones() {
        return $this->phones;
    }

    public function setName($name) {
        $this->name = $name;
    }

    public function setAge($age) {
        $this->age = $age;
    }

    public function setPhones($phones) {
        $this->phones = $phones;
    }

}

<?php

namespace AppBundle\Controller;

use JMS\Serializer\Annotation\Type;

class Telephone {

    /**
     * @Type("string")
     */
    private $phone;

    public function getPhone() {
        return $this->phone;
    }

    public function setPhone($phone) {
        $this->phone = $phone;
    }

}

Answer 1

据我了解，当您执行 $this->get('serializer') 时，您将获得 Symfony Serialization component. I'm not entirely familiar with it (you'll see why in a tick) but their documentation does highlight how to handle object properties 尽管仅用于序列化。

对于您似乎正在寻找的对序列化视图的控制类型，我强烈建议 JMS serializer (and associated bundle)，它可以让您通过注释或外部配置对输出进行更精细的控制。在你的情况下，做：

use JMS\Serializer\Annotation as Serializer;

class Person
{
    /**
     * @Serializer\Type("array<Telephone>")
     */
    private $phones;

可能足以获得您正在寻找的双向序列化。

将复杂对象图序列化为 XML 并返回

Serialize Complex Object Graph to XML and Back

php

symfony

serialization

xml-serialization

symfony-2.7

问题

问题

模型/控制器

使用 JMS 序列化程序的解决方案