Reflection.Emit 实现接口并创建数组 IL
Reflection.Emit Implement interface and create array IL
我正在尝试从界面创建代理 Class。在方法中,我只想收集对象数组中的所有参数并传递给已知方法。所以 faar 我设法让它在没有参数和 return 类型的情况下工作。一旦我尝试创建我的数组,我就会得到 "Additional information: Common Language Runtime detected an invalid program.".. 真的不知道如何从这里调试并且 IL 代码似乎是正确的 (?).
public class Program
{
static void Main(string[] args)
{
var v = CreateProxy<IFoo>();
v.DoSomething();
}
public static void TheMethod(object[] args)
{
}
public interface IFoo
{
void DoSomething();
}
public static T CreateProxy<T>()
{
var interfaceType = typeof(T);
AssemblyName assemblyName = new AssemblyName(string.Format("tmp_{0}", interfaceType.FullName));
string moduleName = string.Format("{0}.dll", assemblyName.Name);
string ns = interfaceType.Namespace;
if (!string.IsNullOrEmpty(ns))
ns += ".";
var assembly = AppDomain.CurrentDomain.DefineDynamicAssembly(assemblyName,AssemblyBuilderAccess.RunAndSave);
var module = assembly.DefineDynamicModule(moduleName, false);
var type = module.DefineType(String.Format("{0}Proxy_{1}", ns, interfaceType.Name), TypeAttributes.Class | TypeAttributes.AnsiClass |TypeAttributes.Sealed |TypeAttributes.NotPublic);
type.AddInterfaceImplementation(interfaceType);
//Constructor
var ctor = type.DefineConstructor(MethodAttributes.Public, CallingConventions.HasThis, new Type[] {});
var generator = ctor.GetILGenerator();
generator.Emit(OpCodes.Ret);
//Methods
foreach (var method in interfaceType.GetMethods())
{
var args = method.GetParameters();
var methodImpl = type.DefineMethod(method.Name, MethodAttributes.Public | MethodAttributes.Virtual, method.ReturnType, (from arg in args select arg.ParameterType).ToArray());
generator = methodImpl.GetILGenerator();
generator.Emit(OpCodes.Nop);
generator.Emit(OpCodes.Ldc_I4_1);
generator.Emit(OpCodes.Newarr, typeof(object));
generator.Emit(OpCodes.Stloc_0);
generator.Emit(OpCodes.Ldloc_0);
generator.Emit(OpCodes.Call, typeof(Program).GetMethod(nameof(Program.TheMethod)));
generator.Emit(OpCodes.Nop);
generator.Emit(OpCodes.Ret);
}
return (T)Activator.CreateInstance(type.CreateType());
}
}
我尝试发出的方法应该如下所示。
public void DoSomething()
{
object[] arr = new object[1];
Program.TheMethod(arr);
}
我在这里错过了什么?
你应该初始化局部变量:
foreach (var method in interfaceType.GetMethods())
{
var args = method.GetParameters();
var methodImpl = type.DefineMethod(method.Name, MethodAttributes.Public | MethodAttributes.Virtual, method.ReturnType, (from arg in args select arg.ParameterType).ToArray());
generator = methodImpl.GetILGenerator();
generator.DeclareLocal(typeof(object[]));
....
....
我正在尝试从界面创建代理 Class。在方法中,我只想收集对象数组中的所有参数并传递给已知方法。所以 faar 我设法让它在没有参数和 return 类型的情况下工作。一旦我尝试创建我的数组,我就会得到 "Additional information: Common Language Runtime detected an invalid program.".. 真的不知道如何从这里调试并且 IL 代码似乎是正确的 (?).
public class Program
{
static void Main(string[] args)
{
var v = CreateProxy<IFoo>();
v.DoSomething();
}
public static void TheMethod(object[] args)
{
}
public interface IFoo
{
void DoSomething();
}
public static T CreateProxy<T>()
{
var interfaceType = typeof(T);
AssemblyName assemblyName = new AssemblyName(string.Format("tmp_{0}", interfaceType.FullName));
string moduleName = string.Format("{0}.dll", assemblyName.Name);
string ns = interfaceType.Namespace;
if (!string.IsNullOrEmpty(ns))
ns += ".";
var assembly = AppDomain.CurrentDomain.DefineDynamicAssembly(assemblyName,AssemblyBuilderAccess.RunAndSave);
var module = assembly.DefineDynamicModule(moduleName, false);
var type = module.DefineType(String.Format("{0}Proxy_{1}", ns, interfaceType.Name), TypeAttributes.Class | TypeAttributes.AnsiClass |TypeAttributes.Sealed |TypeAttributes.NotPublic);
type.AddInterfaceImplementation(interfaceType);
//Constructor
var ctor = type.DefineConstructor(MethodAttributes.Public, CallingConventions.HasThis, new Type[] {});
var generator = ctor.GetILGenerator();
generator.Emit(OpCodes.Ret);
//Methods
foreach (var method in interfaceType.GetMethods())
{
var args = method.GetParameters();
var methodImpl = type.DefineMethod(method.Name, MethodAttributes.Public | MethodAttributes.Virtual, method.ReturnType, (from arg in args select arg.ParameterType).ToArray());
generator = methodImpl.GetILGenerator();
generator.Emit(OpCodes.Nop);
generator.Emit(OpCodes.Ldc_I4_1);
generator.Emit(OpCodes.Newarr, typeof(object));
generator.Emit(OpCodes.Stloc_0);
generator.Emit(OpCodes.Ldloc_0);
generator.Emit(OpCodes.Call, typeof(Program).GetMethod(nameof(Program.TheMethod)));
generator.Emit(OpCodes.Nop);
generator.Emit(OpCodes.Ret);
}
return (T)Activator.CreateInstance(type.CreateType());
}
}
我尝试发出的方法应该如下所示。
public void DoSomething()
{
object[] arr = new object[1];
Program.TheMethod(arr);
}
我在这里错过了什么?
你应该初始化局部变量:
foreach (var method in interfaceType.GetMethods())
{
var args = method.GetParameters();
var methodImpl = type.DefineMethod(method.Name, MethodAttributes.Public | MethodAttributes.Virtual, method.ReturnType, (from arg in args select arg.ParameterType).ToArray());
generator = methodImpl.GetILGenerator();
generator.DeclareLocal(typeof(object[]));
....
....