将数组从 c 传输到 python

Question

我正在将 double 数组从 c 函数转移到 python 函数。我的代码是：
C 代码：

double *compute(int size, const double a[])
{
    double* array;
    array = malloc(sizeof(double)*size);
    for (int i=0; i<size; i++)
    {
    array[i] = 3*a[i];
    }
    //printf("Array in compute-function is: \n[");
    //for(int i = 0; i < size; i++)
        //printf("%f, ", array[i]);
    //printf("]\n");
    return array;
}

pyx 代码：

cdef class ArrayWrapper:
    cdef void* data_ptr
    cdef int size

    cdef set_data(self, int size, void* data_ptr):
        """ Set the data of the array
        This cannot be done in the constructor as it must recieve C-level
        arguments.
        Parameters:
        -----------
        size: int
            Length of the array.
        data_ptr: void*
            Pointer to the data            
        """
        self.data_ptr = data_ptr
        self.size = size

    def __array__(self):
        """ Here we use the __array__ method, that is called when numpy
            tries to get an array from the object."""
        cdef np.npy_intp shape[1]
        shape[0] = <np.npy_intp> self.size
        # Create a 1D array, of length 'size'
        ndarray = np.PyArray_SimpleNewFromData(1, shape,
                                               np.NPY_INT, self.data_ptr)
        return ndarray

    def __dealloc__(self):
        """ Frees the array. This is called by Python when all the
        references to the object are gone. """
        free(<void*>self.data_ptr)


def py_compute(int size, np.ndarray[np.double_t,ndim=1] a):
    """ Python binding of the 'compute' function in 'GNLSE_RHS.c' that does
        not copy the data allocated in C.
    """
    cdef double *array
    cdef np.ndarray ndarray
    # Call the C function
    array = compute(size, <double*> a.data)

    array_wrapper = ArrayWrapper()
    array_wrapper.set_data(size, <void*> array) 
    ndarray = np.array(array_wrapper, copy=False)
    # Assign our object to the 'base' of the ndarray object
    ndarray.base = <PyObject*> array_wrapper
    # Increment the reference count, as the above assignement was done in
    # C, and Python does not know that there is this additional reference
    Py_INCREF(array_wrapper)


    return ndarray

python-代码:

for i in xrange(10):
    x[i] = i;

a = cython_wrapper.py_compute(10, x)
print a

但我的结果是

[         0          0          0 1074266112          0 1075314688          0 1075970048          0 1076363264]

而不是预期的

[  0.   3.   6.   9.  12.  15.  18.  21.  24.  27.]

我的错误在哪里？我假设它与有问题的指针传输有关，但我不确定。

Answer 1

这里的错误是在行

ndarray = np.PyArray_SimpleNewFromData(1, shape,
                                      np.NPY_INT, self.data_ptr)

你告诉 numpy self.data_ptr 指向一个整数数组，不是双精度数组之一。

您可以像这样告诉 numpy 正确的数据类型来修复您的代码：

ndarray = np.PyArray_SimpleNewFromData(1, shape,
                                      np.NPY_DOUBLE, self.data_ptr)

它应该按预期工作。

除此之外，您还可以通过不必传入输入数组的大小来稍微简化包装器代码，因为它已经包含在您传递给 [=15= 的 np.ndarray 中]

def py_compute(np.ndarray[np.double_t,ndim=1] a):
    """ Python binding of the 'compute' function in 'GNLSE_RHS.c' that does
        not copy the data allocated in C.
    """
    cdef double *array
    cdef np.ndarray ndarray
    cdef size = a.shape[0]

    # Call the C function
    array = compute(size, &a[0])

    array_wrapper = ArrayWrapper()
    array_wrapper.set_data(size, <void*> array) 
    ndarray = np.array(array_wrapper, copy=False)
    # Assign our object to the 'base' of the ndarray object
    ndarray.base = <PyObject*> array_wrapper
    # Increment the reference count, as the above assignement was done in
    # C, and Python does not know that there is this additional reference
    Py_INCREF(array_wrapper)


    return ndarray

将数组从 c 传输到 python

Transferring arrays from c to python

c

python

cython

python-2.7