oracle中如何通过ROWID查找分区?
How to find the partition by ROWID in oracle?
我在回历月(日期)为 table(测试)创建了分区,
oracle中如何通过ROWID匹配特定分区?
试试这个:
SELECT dbms_rowid.rowid_object(ROWID) data_object_id
FROM test;
要获取您可以使用的分区名称
SELECT partition_name
from user_tab_partitions
where table_name='test'
select object_name tab_name, subobject_name parttition from user_objects where object_id =dbms_rowid.rowid_object('xxxxx');
非常简单,使用 DBMS_RowID 和 dba_objects。
select *
from dba_objects
where data_object_id = dbms_rowid.rowid_object(ROWID_OF_THE_ROW)
这里有更多提示和观察:https://oraclesponge.wordpress.com/2006/05/11/getting-the-subpartition-name-for-a-row/
我在回历月(日期)为 table(测试)创建了分区, oracle中如何通过ROWID匹配特定分区?
试试这个:
SELECT dbms_rowid.rowid_object(ROWID) data_object_id
FROM test;
要获取您可以使用的分区名称
SELECT partition_name
from user_tab_partitions
where table_name='test'
select object_name tab_name, subobject_name parttition from user_objects where object_id =dbms_rowid.rowid_object('xxxxx');
非常简单,使用 DBMS_RowID 和 dba_objects。
select *
from dba_objects
where data_object_id = dbms_rowid.rowid_object(ROWID_OF_THE_ROW)
这里有更多提示和观察:https://oraclesponge.wordpress.com/2006/05/11/getting-the-subpartition-name-for-a-row/