在nodejs中使用promises执行一系列命令

Using promises to execute a series of commands in nodejs

我想在nodejs中使用Q promises通过串行线逐步处理一系列命令。

var cmdArr = ['cmd1', 'cmd2','cmd3'];

我不确定如何构建它。我想过这样的事情,但没有奏效:

Q().then(function() {
  cmdArr.forEach(command) {
     //here to initialize the promise??
  }
});

重要的是保持顺序并且能够在每个步骤之间使用 Q.delay。

假设您要执行的命令是某种异步函数调用:

var Q = require('q');

// This is the function you want to perform. For example purposes, all this
// does is use `setTimeout` to fake an async operation that takes some time.
function asyncOperation(input, cb) {
  setTimeout(function() {
    cb();
  }, 250);
};

function performCommand(command) {
  console.log('performing command', command);
  // Here the async function is called with an argument (`command`),
  // and once it's done, an extra delay is added (this could be optional
  // depending on the command that is executed).
  return Q.nfcall(asyncOperation, command).delay(1000);
}

// Set up a sequential promise chain, where a command is executed
// only when the previous has finished.
var chain = Q();
[ 'cmd1', 'cmd2', 'cmd3' ].forEach(function(step) {
  chain = chain.then(performCommand.bind(null, step));
});

// At this point, all commands have been executed.
chain.then(function() {
  console.log('all done!');
});

我对q不是很熟悉,所以可能会做得更好。

为了完整起见,这里有一个使用 bluebird 的版本:

var Promise = require('bluebird');

...

var asyncOperationAsPromised = Promise.promisify(asyncOperation);

function performCommand(command) {
  console.log('performing command', command);
  return asyncOperationAsPromised(command).delay(1000);
}

Promise.each(
  [ 'cmd1', 'cmd2', 'cmd3' ],
  performCommand.bind(null)
).then(function() {
  console.log('all done!');
});

对数组进行一系列异步操作排序的常见设计模式是使用 .reduce(),如下所示:

var cmdArr = ['cmd1', 'cmd2','cmd3'];

cmdArr.reduce(function(p, item) {
    return p.delay(1000).then(function() {
        // code to process item here
        // if this code is asynchronous, it should return a promise here
        return someAyncOperation(item);
    });
}, Q()).then(function(finalResult) {
    // all items done here
});

请注意,我还展示了您可以根据要求在何处插入 Q .delay()