试图操纵从 cURL 调用返回的 json

Trying to manipulate the returned json from a cURL call

这个问题让我很困惑。这是我的代码:

try {
    //API Url
    $url =   'https:<REST OF URL>';

    //Initiate cURL.
    $ch = curl_init($url);

    //The JSON data.
    $jsonData = array(
        'UserName' => '<HIDDEN>',
        'Password' => '<HIDDEN>'
    );

    //Encode the array into JSON.
    $jsonDataEncoded = json_encode($jsonData);

    //Tell cURL that we want to send a POST request.
    curl_setopt($ch, CURLOPT_POST, 1);

    //Attach our encoded JSON string to the POST fields.
    curl_setopt($ch, CURLOPT_POSTFIELDS, $jsonDataEncoded);

    //Set the content type to application/json
    curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json')); 

    curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);

    //Execute the request
    $content = curl_exec($ch);

catch(Exception $e) {   
    trigger_error(sprintf(
        'Curl failed with error #%d: %s',
        $e->getCode(), $e->getMessage()),
        E_USER_ERROR);
}

我正在使用浏览器 运行 php 脚本,输出似乎是 json 格式,这正是我需要的。然而,当我添加 json 解码并尝试 print_r 或 var_dump 输出时,我只是得到一个 boolean(true) 或 int(1),它不想将数据放入大批。同样奇怪且最有可能相关的是,上面的代码没有使用 print_r,或 var_dump,甚至没有回显,但它仍然将 json 格式打印到屏幕上?

如有任何帮助,我们将不胜感激。

编辑

这是出现在屏幕上的 json 输出:

 {"AvailableAdvisers":[{"AdviserId":"1345678","BusinessEntityName":"Bob Smith Finance","FullName":"Bob Smith"},{"AdviserId":"12345678","BusinessEntityName":"Globe Home Loans Pty Ltd","FullName":"Jane Doe"}],"FirstName":"Sam","LastName":"Sung","LendingPartnerStaffId":"12345674356","Locations":[{"LendingPartnerLocationId":"123467867647","Name":"Bank"},{"LendingPartnerLocationId":"12324354545","Name":"Jane Smith"}],"UserName":"Username"}

好的,看来我明白你的意思了。

因此,要将 curl 响应放入 $content 变量中,您可能需要添加行:

 curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); 

在你的curl_exec

之前

但是 curl 响应如何出现在页面上的奇迹是真正的谜:-)