比较 XML 忽略元素顺序

Question

使用 XMLUnit 2 如何在不考虑元素顺序的情况下比较两个文档？

我得到了，但显然 v2 中的新 API 不再具有上述方法。

这是我当前的代码：

Diff diff = DiffBuilder.compare(expected)
            .withTest(actual)
            .ignoreComments()
            .ignoreWhitespace()
            .checkForSimilar()
            .build();

assertFalse(diff.hasDifferences());

编辑 Stefan Bodewigs 评论：

这些是我与上面的代码片段进行比较的两个字符串：

String expected = "<root><foo>FOO</foo><bar>BAR</bar></root>";
String actual = "<root><bar>BAR</bar><foo>FOO</foo></root>";

报告的差异

Expected element tag name 'foo' but was 'bar' - comparing <foo...> at /root[1]/foo[1] to <bar...> at /root[1]/bar[1] (DIFFERENT)
Expected text value 'FOO' but was 'BAR' - comparing <foo ...>FOO</foo> at /root[1]/foo[1]/text()[1] to <bar ...>BAR</bar> at /root[1]/bar[1]/text()[1] (DIFFERENT)
Expected element tag name 'bar' but was 'foo' - comparing <bar...> at /root[1]/bar[1] to <foo...> at /root[1]/foo[1] (DIFFERENT)
Expected text value 'BAR' but was 'FOO' - comparing <bar ...>BAR</bar> at /root[1]/bar[1]/text()[1] to <foo ...>FOO</foo> at /root[1]/foo[1]/text()[1] (DIFFERENT)

Answer 1

可能需要在 2.x 文档中变得更清楚的一个区别是默认值 ElementSelector - 大致是 1.x 中的 ElementQualifier。其中 1.x 默认按名称匹配元素， 2.x 默认按顺序匹配元素。也许这是个坏主意。

如果您切换到匹配元素名称，您的 Diff 应该可以工作。

.withNodeMatcher(new DefaultNodeMatcher(ElementSelectors.byName))

比较 XML 忽略元素顺序

Compare XML ignoring element order

xml

diff

xmlunit

xmlunit-2