如何 ORDER BY last_visit 并为用户显示最近的访问者？

Question

以下 public 函数显示用户个人资料的访问者。我想做的是按最近的访问者排序结果。我认为最好的方法是在左侧 JOIN 之前添加 ORDER BY last_visit。但这破坏了脚本，我收到了 'no results' 消息。 last_visits 有一个时间戳数据类型 btw。

public function getVisitors($count = 10, $page = 0){
    $result = $this->_db->query('
        SELECT
            `visited_users`.*,
            `users`.*,
            NOW() as now_t
        FROM
            `visited_users`
        ORDER BY last_visit  
        LEFT JOIN `users` ON `users`.`id` = `visited_users`.`user_id`
        WHERE
            `visited_users`.`visited_id` = ?
        LIMIT '.$count*$page.','.$count, array($this->_data->id));
    return $result->results();
}

Answer 1

正确的 SQL 语法要求 ORDER BY 位于 WHERE 子句之后。试试这个。

public function getVisitors($count = 10, $page = 0){
    $result = $this->_db->query('
        SELECT
            `visited_users`.*,
            `users`.*,
            NOW() as now_t
        FROM
            `visited_users`
        LEFT JOIN `users` ON `users`.`id` = `visited_users`.`user_id`
        WHERE
            `visited_users`.`visited_id` = ?
        ORDER BY last_visit  
        LIMIT '.$count*$page.','.$count, array($this->_data->id));
    return $result->results();
}

如何 ORDER BY last_visit 并为用户显示最近的访问者？

How do I ORDER BY last_visit and display the most recent visitor for a user?

php

mysql

oop

sql-order-by