玩！框架 - return 多个列表到模板

Question

我有 3 个类，我想要 return 3 个列表到模板中，在 Form 中使用我的数据库是 MongoDB

def addCourse = Action.async {implicit request =>
  val teacherCollection = db.collection[BSONCollection]("Teacher")
   val courseColl = subjectCollection.find(BSONDocument()).cursor[Subject].collect[List]()
   val teacherColl = teacherCollection.find(BSONDocument()).cursor[Teacher].collect[List]()

    courseColl.map { course =>
      val sam = teacherColl.map{teacher=>
        teacher
      }
    Ok(views.html.Course.addNewCourse(course,sam,Course.form))
   }
  }

模板代码：

   @(subject:List[models.Subject],teacher:List[models.Teacher],myForm: Form[models.Course])

我遇到一个错误：类型不匹配，预期为 List[Teacher]，实际为 Future[List[Teacher]]

我要做什么？

注意：如果我将 Ok(views...) 放入 val sam 映射，编译器会显示错误，这听起来像是异步错误，因为 "async" 将是红色的

 Error:(59, -1) Play 2 Compiler: 
 /app/controllers/School.scala:59: type mismatch;
found   : Unit
  required: play.api.mvc.Result

Answer 1

我已经用 flatMap 解决了这个问题

courseColl.flatMap { course =>
  teacherColl.flatMap { teacher =>
    semesterColl.map { semester =>
      Ok(views.html.Course.addNewCourse(course, teacher, semester,    Course.form))
    }
  }
}

玩！框架 - return 多个列表到模板

Play! Framework - return multiple list to template

scala

mongodb

playframework

reactivemongo

twirl