从 WPF c# 中读取 XML
Reading in XML from WPF c#
我正在努力将 "GPX" 文件读入 WPF (c#) 项目。下面提供了示例 GPX。我尝试了很多不同的选项,但结果相同。
文档加载正常,但我无法将其分解以直接访问节点。
如有任何帮助,我们将不胜感激。
谢谢。
private void Simple_Click(object sender, RoutedEventArgs e)
{
XmlDocument xml = new XmlDocument();
xml.Load(@"C:\Users\Jonathon\Desktop\GPX_Data.gpx");
XmlNodeList nodes = xml.SelectNodes("trkpt"); // have tried: double '/' to get nodes at any level (XPath syntax)
//XmlNodeList nodes = xml.SelectNodes("/gpx/trk/trkseg/trkpt");
int count = 0;
foreach (XmlNode xn in nodes)
{
count++;
}
}
}
示例 GPX 文件
<?xml version="1.0" encoding="UTF-8"?>
<gpx version="1.1" creator="Endomondo.com"
xsi:schemaLocation="http://www.topografix.com/GPX/1/1
http://www.topografix.com/GPX/1/1/gpx.xsd
http://www.garmin.com/xmlschemas/GpxExtensions/v3
http://www.garmin.com/xmlschemas/GpxExtensionsv3.xsd
http://www.garmin.com/xmlschemas/TrackPointExtension/v1
http://www.garmin.com/xmlschemas/TrackPointExtensionv1.xsd"
xmlns="http://www.topografix.com/GPX/1/1"
xmlns:gpxtpx="http://www.garmin.com/xmlschemas/TrackPointExtension/v1"
xmlns:gpxx="http://www.garmin.com/xmlschemas/GpxExtensions/v3"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<metadata>
<author>
<name>Jonathon Ralfe</name>
<email id="jonathon" domain="ralfe.net"/>
</author>
<link href="http://www.endomondo.com">
<text>Endomondo</text>
</link>
<time>2015-01-27T18:31:26Z</time>
</metadata>
<trk>
<src>http://www.endomondo.com/</src>
<link href="https://www.endomondo.com/workouts/463986953/2256850">
<text>endomondo</text>
</link>
<type>SKIING_DOWNHILL</type>
<trkseg>
<trkpt lat="45.576892" lon="6.894079">
<time>2015-01-26T09:49:57Z</time>
</trkpt>
<trkpt lat="45.576892" lon="6.894079">
<ele>1595.0</ele>
<time>2015-01-26T09:49:59Z</time>
</trkpt>
<trkpt lat="45.577109" lon="6.893946">
<ele>1581.0</ele>
<time>2015-01-26T09:51:46Z</time>
</trkpt>
<trkpt lat="45.5772" lon="6.894084">
<ele>1575.0</ele>
<time>2015-01-26T09:52:02Z</time>
</trkpt>
<trkpt lat="45.577247" lon="6.894212">
<ele>1577.0</ele>
<time>2015-01-26T09:52:05Z</time>
</trkpt>
<trkpt lat="45.577317" lon="6.89452">
<ele>1589.0</ele>
<time>2015-01-26T09:52:11Z</time>
</trkpt>
那是因为你的xml有命名空间,所以查询数据的时候要设置命名空间。
考虑这种方法:
XmlNamespaceManager nsmgr = new XmlNamespaceManager(xml.NameTable);
nsmgr.AddNamespace("x", "http://www.topografix.com/GPX/1/1");
XmlNodeList nodes = xml.SelectNodes("//x:trkpt", nsmgr);
这里我们正在创建 NamespaceManager,根据您的数据 xmlns="http://www.topografix.com/GPX/1/1"
属性设置命名空间,并在 XPath 中使用此命名空间。
通过 XPath 选择:
foreach(XElement aElement in xml.XPathSelectElements("/trk/trkseg").Elements())
{
foreach(XNode aXNode in aElement.Nodes())
{
//Access subnodes of trkpt
}
}
我正在努力将 "GPX" 文件读入 WPF (c#) 项目。下面提供了示例 GPX。我尝试了很多不同的选项,但结果相同。
文档加载正常,但我无法将其分解以直接访问节点。
如有任何帮助,我们将不胜感激。
谢谢。
private void Simple_Click(object sender, RoutedEventArgs e)
{
XmlDocument xml = new XmlDocument();
xml.Load(@"C:\Users\Jonathon\Desktop\GPX_Data.gpx");
XmlNodeList nodes = xml.SelectNodes("trkpt"); // have tried: double '/' to get nodes at any level (XPath syntax)
//XmlNodeList nodes = xml.SelectNodes("/gpx/trk/trkseg/trkpt");
int count = 0;
foreach (XmlNode xn in nodes)
{
count++;
}
}
}
示例 GPX 文件
<?xml version="1.0" encoding="UTF-8"?>
<gpx version="1.1" creator="Endomondo.com"
xsi:schemaLocation="http://www.topografix.com/GPX/1/1
http://www.topografix.com/GPX/1/1/gpx.xsd
http://www.garmin.com/xmlschemas/GpxExtensions/v3
http://www.garmin.com/xmlschemas/GpxExtensionsv3.xsd
http://www.garmin.com/xmlschemas/TrackPointExtension/v1
http://www.garmin.com/xmlschemas/TrackPointExtensionv1.xsd"
xmlns="http://www.topografix.com/GPX/1/1"
xmlns:gpxtpx="http://www.garmin.com/xmlschemas/TrackPointExtension/v1"
xmlns:gpxx="http://www.garmin.com/xmlschemas/GpxExtensions/v3"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<metadata>
<author>
<name>Jonathon Ralfe</name>
<email id="jonathon" domain="ralfe.net"/>
</author>
<link href="http://www.endomondo.com">
<text>Endomondo</text>
</link>
<time>2015-01-27T18:31:26Z</time>
</metadata>
<trk>
<src>http://www.endomondo.com/</src>
<link href="https://www.endomondo.com/workouts/463986953/2256850">
<text>endomondo</text>
</link>
<type>SKIING_DOWNHILL</type>
<trkseg>
<trkpt lat="45.576892" lon="6.894079">
<time>2015-01-26T09:49:57Z</time>
</trkpt>
<trkpt lat="45.576892" lon="6.894079">
<ele>1595.0</ele>
<time>2015-01-26T09:49:59Z</time>
</trkpt>
<trkpt lat="45.577109" lon="6.893946">
<ele>1581.0</ele>
<time>2015-01-26T09:51:46Z</time>
</trkpt>
<trkpt lat="45.5772" lon="6.894084">
<ele>1575.0</ele>
<time>2015-01-26T09:52:02Z</time>
</trkpt>
<trkpt lat="45.577247" lon="6.894212">
<ele>1577.0</ele>
<time>2015-01-26T09:52:05Z</time>
</trkpt>
<trkpt lat="45.577317" lon="6.89452">
<ele>1589.0</ele>
<time>2015-01-26T09:52:11Z</time>
</trkpt>
那是因为你的xml有命名空间,所以查询数据的时候要设置命名空间。
考虑这种方法:
XmlNamespaceManager nsmgr = new XmlNamespaceManager(xml.NameTable);
nsmgr.AddNamespace("x", "http://www.topografix.com/GPX/1/1");
XmlNodeList nodes = xml.SelectNodes("//x:trkpt", nsmgr);
这里我们正在创建 NamespaceManager,根据您的数据 xmlns="http://www.topografix.com/GPX/1/1"
属性设置命名空间,并在 XPath 中使用此命名空间。
通过 XPath 选择:
foreach(XElement aElement in xml.XPathSelectElements("/trk/trkseg").Elements())
{
foreach(XNode aXNode in aElement.Nodes())
{
//Access subnodes of trkpt
}
}