如何在 SQL 服务器 table 列中查找相同值的行

Question

我有这样的查询：

SELECT
   *
FROM 
   sub_aminer_paper
WHERE 
   p_abstract LIKE (
                    SELECT 
                       p_abstract
                    FROM 
                       sub_aminer_paper
                    GROUP BY 
                       p_abstract
                    HAVING 
                       COUNT(pid) > 1
                    )
AND 
   pid IN (784502,787096,789536)
ORDER BY
   pid

我想从中检索列 p_abstract 具有相同值的行，其中数据类型为 text 中的 p_abstract 列。执行此查询时，出现以下错误：

The text, ntext, and image data types cannot be compared or sorted, except when using IS NULL or LIKE operator.

Answer 1

检查这是否是您所期望的。

SELECT *
FROM sub_aminer_paper
WHERE pid IN (784502,787096,789536)
and CAST(p_abstract AS varchar(max)) in (
    SELECT CAST(p_abstract AS varchar(max))
    FROM   sub_aminer_paper
    WHERE pid IN (784502,787096,789536)
    Group BY CAST(p_abstract AS varchar(max))
    having count(*) > 1)
ORDER by pid

Answer 2

您需要比较文本字段的校验和

WITH PAPERS AS(
    SELECT 
           pid,
           BINARY_CHECKSUM(p_abstract) as chksum
        FROM 
           sub_aminer_paper
), DOUBLES AS (
    SELECT 
        chksum
        ,qty = COUNT(*)
      FROM
         papers
      GROUP BY
        chksum
      HAVING 
        COUNT(*) > 1
)
SELECT *
    FROM 
        PAPERS P
        JOIN DOUBLES D ON P.chksum = D.chksum

如何在 SQL 服务器 table 列中查找相同值的行

How to find rows of same value in SQL Server table column

sql-server

matching