为什么 listView 中的名称不断变化?
Why the name in listView keep changing?
我在 Activity A 中有一个 listView
,如下所示。所有的值和名称实际上都是 return 从 Activity C 到 B 然后只有 A.
单击第一个列表时,它应该在 editText
B 上显示文本 Project
和值 3
。但它显示的 Medical
实际上是从最后一个列表。
我把值从3改成43,return改成A后,名字就变了。我应该怎么做才能使名称保持不变?
Activity一个
ArrayAdapter<String> adapter;
ArrayList<String> m_listItems = new ArrayList<String>();
int mClickedPosition;
adapter=new ArrayAdapter<String (getActivity(),R.layout.claims,R.id.textView1,m_listItems);
listV = (ListView) claims.findViewById(R.id.listView1);
listV.setOnItemClickListener(new AdapterView.OnItemClickListener() { // if list clicked
public void onItemClick(AdapterView<?> listView, View view,
int position, long id) {
mClickedPosition = position;
if (name.equals("Project")) {
String temp[] = m_listItems.get(position).split("\s\s+");
result = temp[temp.length - 1].trim();
result = result.replace("RM","");
Intent intent = new Intent(Claims1.this.getActivity(), Project1.class);
intent.putExtra("bitmap", true); // image
intent.putExtra("name", name);
intent.putExtra("result", result);
startActivityForResult(intent, 0);
Log.e("RESULT", "Result= " + result);
}
else if(name.equals("Medical"))
{
String temp[] = m_listItems.get(position).split("\s\s+");
result = temp[temp.length - 1].trim();
result = result.replace("RM","");
Intent intent = new Intent(Claims1.this.getActivity(), Medical.class);
intent.putExtra("bitmap", true);
intent.putExtra("name", name);
intent.putExtra("result", result);
startActivityForResult(intent, 1);
}
}
});
return claims;
}
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
switch (requestCode) {
case 0: // for Project
result = data.getStringExtra("text"); //get from B
name = data.getStringExtra("a");
description = data.getStringExtra("c");
as = Long.parseLong(result);
Log.d("FIRST", "result:" + result);
Text = " " + name + " " + "RM" + result + "";
if (mClickedPosition == -1) { // if is icon button clicked
m_listItems.add(Text);
} else {
m_listItems.set(mClickedPosition, Text);
}
adapter.notifyDataSetChanged();
listV.setAdapter(adapter);
break;
case 1: // for Medical
result = data.getStringExtra("text");
name = data.getStringExtra("a");
description = data.getStringExtra("c");
as = Long.parseLong(result);
Log.d("FIRST", "result:" + result);
Text = " " + name + " " + "RM" + result + "";
// m_listItems.clear();
if (mClickedPosition==-1)
{
m_listItems.add(Text);
}
else
{
m_listItems.set(mClickedPosition, Text);
}
adapter.notifyDataSetChanged();
listV.setAdapter(adapter);
break;
Activity B(项目 1)
if(getIntent().getExtras()!=null) { //if has value pass from A
final String Amount = getIntent().getExtras().getString("result");
final String description1 = getIntent().getExtras().getString("description");
txt1.setText(description1);
txt.setText(Amount);
}
b.setOnClickListener(new View.OnClickListener() { // return to A
public void onClick(View arg0) {
Intent returnIntent = new Intent();
a = "Project";
text = txt.getText().toString(); // amount
returnIntent.putExtra("text", text);
returnIntent.putExtra("a", a);
returnIntent.putExtra("c", c); // receive from Activity C
setResult(Activity.RESULT_OK, returnIntent);
finish();
}
});
viewImage.setImageBitmap(Global.img); // receive from C
}
注意到 Activity A 中的 result
代表值 3,5 而 name
代表 project
和 Medical
。我怎样才能解决这个问题 ?请帮助。
据我了解,Activity A 中的变量 name
包含先前结果值(来自 Activity B),而不是来自您在列表视图中单击的行,即 "Medical" 您之前从 Activity B 获得的值,该值由变量 name
持有,并且在您的列表视图点击事件中,您检查了 name
是 "Medical" 还是 "Project" (在这种情况下,它是 "Medical",因此医疗 activity 已启动)。
一种解决方案是从列表视图中获取值("Project/Medical")。
试试这个代码。
Activity一个
mClickedPosition = position;
String temp[] = m_listItems.get(position).split("\s\s+");
result = temp[temp.length - 1].trim();
result = result.replace("RM","");
name = temp[1].trim();
if (name.equals("Project")) {
Intent intent = new Intent(Claims1.this.getActivity(), Project1.class);
intent.putExtra("bitmap", true);
intent.putExtra("name", name);
intent.putExtra("result", result);
startActivityForResult(intent, 0);
Log.e("RESULT", "Result= " + result);
}
else if(name.equals("Medical"))
{
Intent intent = new Intent(Claims1.this.getActivity(), Medical.class);
intent.putExtra("bitmap", true);
intent.putExtra("name", name);
intent.putExtra("result", result);
startActivityForResult(intent, 1);
}
我在 Activity A 中有一个 listView
,如下所示。所有的值和名称实际上都是 return 从 Activity C 到 B 然后只有 A.
单击第一个列表时,它应该在 editText
B 上显示文本 Project
和值 3
。但它显示的 Medical
实际上是从最后一个列表。
我把值从3改成43,return改成A后,名字就变了。我应该怎么做才能使名称保持不变?
Activity一个
ArrayAdapter<String> adapter;
ArrayList<String> m_listItems = new ArrayList<String>();
int mClickedPosition;
adapter=new ArrayAdapter<String (getActivity(),R.layout.claims,R.id.textView1,m_listItems);
listV = (ListView) claims.findViewById(R.id.listView1);
listV.setOnItemClickListener(new AdapterView.OnItemClickListener() { // if list clicked
public void onItemClick(AdapterView<?> listView, View view,
int position, long id) {
mClickedPosition = position;
if (name.equals("Project")) {
String temp[] = m_listItems.get(position).split("\s\s+");
result = temp[temp.length - 1].trim();
result = result.replace("RM","");
Intent intent = new Intent(Claims1.this.getActivity(), Project1.class);
intent.putExtra("bitmap", true); // image
intent.putExtra("name", name);
intent.putExtra("result", result);
startActivityForResult(intent, 0);
Log.e("RESULT", "Result= " + result);
}
else if(name.equals("Medical"))
{
String temp[] = m_listItems.get(position).split("\s\s+");
result = temp[temp.length - 1].trim();
result = result.replace("RM","");
Intent intent = new Intent(Claims1.this.getActivity(), Medical.class);
intent.putExtra("bitmap", true);
intent.putExtra("name", name);
intent.putExtra("result", result);
startActivityForResult(intent, 1);
}
}
});
return claims;
}
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
switch (requestCode) {
case 0: // for Project
result = data.getStringExtra("text"); //get from B
name = data.getStringExtra("a");
description = data.getStringExtra("c");
as = Long.parseLong(result);
Log.d("FIRST", "result:" + result);
Text = " " + name + " " + "RM" + result + "";
if (mClickedPosition == -1) { // if is icon button clicked
m_listItems.add(Text);
} else {
m_listItems.set(mClickedPosition, Text);
}
adapter.notifyDataSetChanged();
listV.setAdapter(adapter);
break;
case 1: // for Medical
result = data.getStringExtra("text");
name = data.getStringExtra("a");
description = data.getStringExtra("c");
as = Long.parseLong(result);
Log.d("FIRST", "result:" + result);
Text = " " + name + " " + "RM" + result + "";
// m_listItems.clear();
if (mClickedPosition==-1)
{
m_listItems.add(Text);
}
else
{
m_listItems.set(mClickedPosition, Text);
}
adapter.notifyDataSetChanged();
listV.setAdapter(adapter);
break;
Activity B(项目 1)
if(getIntent().getExtras()!=null) { //if has value pass from A
final String Amount = getIntent().getExtras().getString("result");
final String description1 = getIntent().getExtras().getString("description");
txt1.setText(description1);
txt.setText(Amount);
}
b.setOnClickListener(new View.OnClickListener() { // return to A
public void onClick(View arg0) {
Intent returnIntent = new Intent();
a = "Project";
text = txt.getText().toString(); // amount
returnIntent.putExtra("text", text);
returnIntent.putExtra("a", a);
returnIntent.putExtra("c", c); // receive from Activity C
setResult(Activity.RESULT_OK, returnIntent);
finish();
}
});
viewImage.setImageBitmap(Global.img); // receive from C
}
注意到 Activity A 中的 result
代表值 3,5 而 name
代表 project
和 Medical
。我怎样才能解决这个问题 ?请帮助。
据我了解,Activity A 中的变量 name
包含先前结果值(来自 Activity B),而不是来自您在列表视图中单击的行,即 "Medical" 您之前从 Activity B 获得的值,该值由变量 name
持有,并且在您的列表视图点击事件中,您检查了 name
是 "Medical" 还是 "Project" (在这种情况下,它是 "Medical",因此医疗 activity 已启动)。
一种解决方案是从列表视图中获取值("Project/Medical")。
试试这个代码。 Activity一个
mClickedPosition = position;
String temp[] = m_listItems.get(position).split("\s\s+");
result = temp[temp.length - 1].trim();
result = result.replace("RM","");
name = temp[1].trim();
if (name.equals("Project")) {
Intent intent = new Intent(Claims1.this.getActivity(), Project1.class);
intent.putExtra("bitmap", true);
intent.putExtra("name", name);
intent.putExtra("result", result);
startActivityForResult(intent, 0);
Log.e("RESULT", "Result= " + result);
}
else if(name.equals("Medical"))
{
Intent intent = new Intent(Claims1.this.getActivity(), Medical.class);
intent.putExtra("bitmap", true);
intent.putExtra("name", name);
intent.putExtra("result", result);
startActivityForResult(intent, 1);
}