奇怪的摇摆 Java 计划 213a。使用多个 if else 语句

Question

您刚刚开始从事程序员工作。您已同意以下补偿方案。

• 您每小时支付 30 美元。 • 如果您在一天中的任何时间工作超过 8 小时，您每小时可额外赚取 25.50 美元。
• 任何一周超过 40 小时，您每小时可额外赚取 15 美元。
• 周六工作赚取的任何金额均可获得 125% 的奖金，周日工作可获得 50% 的奖金。

您的输入文件将是您从周日开始的一周内每天工作的小时数。您需要编写一个程序来继续处理该文件，以计算您每周工作的总工资，直到到达文件末尾。每行输入将包含一个星期的小时数（每行 7 个整数，每个小于或等于 24）。输出带美元符号的总工资，四舍五入为每周工作的最接近的便士。

import java.util.*;
import java.io.*;

public class prog213a
{
public static void main (String args [])
{
    Scanner inFile = null; //setting scanned file as null

    double weeklyPay=0,sunPay=0, monPay=0, tuesPay=0, wedPay=0, thurPay=0, friPay=0, satPay=0;

    try
    {
        inFile =new Scanner(new File("prog213a.dat")); //reading file
    }
    catch(Exception e) //if file doesn't exist
    {
        System.out.println("File not found"); //output that file doesn't exist
        System.exit (0); //exit program
    }

    while (inFile.hasNext())
    {
        final int sunHours = inFile.nextInt();
        final int monHours = inFile.nextInt();
        final int tuesHours = inFile.nextInt();
        final int wedHours = inFile.nextInt();
        final int thurHours = inFile.nextInt();
        final int friHours = inFile.nextInt();
        final int satHours = inFile.nextInt();
        final int weeklyHours = monHours + tuesHours + wedHours + thurHours + friHours;
        if(sunHours>8){
            sunPay=((sunHours-8)*55.50)+240;
        }
        else{
            sunPay= sunHours*30;
        }
        if(monHours>8){
            monPay=((monHours-8)*55.50)+240;
        }
        else{
            monPay= monHours*30;
        }
        if(tuesHours>8){
            tuesPay=((tuesHours-8)*55.50)+240;
        }
        else{
            tuesPay= tuesHours*30;
        }
        if(wedHours>8){
            wedPay=((wedHours-8)*55.50)+240;
        }
        else{
            wedPay= wedHours*30;
        }
        if(thurHours>8){
            thurPay=((thurHours-8)*55.50)+240;
        }
        else{
            thurPay= thurHours*30;
        }
        if(friHours>8){
            friPay=((friHours-8)*55.50)+240;
        }
        else{
            friPay= friHours*30;
        }
        if(satHours>8){
            satPay=((satHours-8)*55.50)+240;
        }
        if(weeklyHours>40){
            weeklyPay=((weeklyHours-40)*45)+1200;
        }
        System.out.print(sunPay);
    }
  }
}

到目前为止，我已经编写了这段代码，但是当我去测试该程序以查看它是否适合周日支付时，我得到了这个“295.5210.0180.0” 我需要帮助来修复此代码，以便它适合参数并输出正确的答案。

数据文件：

9 8 10 8 9 9 5

7 8 8 8 0 8 9

6 10 5 0 0 0 0

Answer 1

我能够自己修复代码。

    Scanner inFile = null; //setting scanned file as null

    double weeklyPay=0,sunPay=0, monPay=0, tuesPay=0, wedPay=0, thurPay=0, friPay=0, satPay=0, overPay=0; //initializing variables
    int weekNumber=1; //which week it is

    DecimalFormat twodigits= new DecimalFormat("0.00"); //formating numbers

    try
    {
        inFile =new Scanner(new File("prog213a.dat")); //reading file 
    }
    catch(Exception e) //if file doesn't exist
    {
        System.out.println("File not found"); //output that file doesn't exist
        System.exit (0); //exit program
    }

    while (inFile.hasNextLine()) //while the file has a next line of data
    {
        System.out.println("Week " + weekNumber + ": "); //header

        int sunHours = inFile.nextInt();  //getting the hours for each day
        int monHours = inFile.nextInt();
        int tuesHours = inFile.nextInt();
        int wedHours = inFile.nextInt();
        int thurHours = inFile.nextInt();
        int friHours = inFile.nextInt();
        int satHours = inFile.nextInt();
        int weeklyHours = monHours + tuesHours + wedHours + thurHours + friHours; //weekly hours is summation of hours

        System.out.println(sunHours + " " + monHours + " " + tuesHours + " " + wedHours + " " + thurHours + " " + friHours + " " + satHours); //output

        //calculating daily pay depending on the specifications

        if(sunHours>8) 
            sunPay=(((sunHours-8)*55.50)+240)*2.25;
        else
            sunPay=(sunHours*30)*2.25;

        if(monHours>8)
            monPay=((monHours-8)*55.50)+240;
        else
            monPay= monHours*30;

        if(tuesHours>8)
            tuesPay=((tuesHours-8)*55.50)+240;
        else
            tuesPay= tuesHours*30;

        if(wedHours>8)
            wedPay=((wedHours-8)*55.50)+240;
        else
            wedPay= wedHours*30;

        if(thurHours>8)
            thurPay=((thurHours-8)*55.50)+240;
        else
            thurPay= thurHours*30;

        if(friHours>8)
            friPay=((friHours-8)*55.50)+240;
        else
            friPay= friHours*30;

        if(satHours>8)
            satPay=(((satHours-8)*55.50)+240)*1.5;
        else
            satPay= (satHours*30)*1.5;


        if(weeklyHours>40){
            overPay=(weeklyHours-40)*45; //pay if weekly hours are over 40
            weeklyPay=(sunPay + monPay + tuesPay + wedPay + thurPay + friPay + satPay + overPay); //pay including over pay
            System.out.println(twodigits.format(weeklyPay));//output
        }
        else{
            weeklyPay=(sunPay+monPay+tuesPay+wedPay+thurPay+friPay+satPay); //pay if hours is less than 40
            System.out.println(twodigits.format(weeklyPay)); //output
        }

        weekNumber++; //increments the week number
        System.out.println(); //blank line
    }

奇怪的摇摆 Java 计划 213a。使用多个 if else 语句

Weird Wags Java Program 213a. Using several if else statements

java

computer-science