JPAQuery (QueryDSL) 中的非致命用户错误

Question

我必须使用 QueryDSL / JPAQuery 添加搜索功能。搜索应使用 table 由父 ID 组成：

ID   LABEL  P_ID
1    A      null 
2    AB     1
3    ABC    2

一个简单的 SQL 语句给出了正确的结果：

SELECT * FROM ACT
JOIN ORG DEPT ON ACT.ORGID = DEPT.ID
JOIN ORG DEPT2 ON DEPT.P_ID = DEPT2.ID
WHERE DEPT.P_ID = 123

我面临的问题是我必须使用现有的查询对象创建相应的 QueryDSL/JPAQuery。

我的代码是：

query.join(act.org, dept).on(act.org.id.eq(dept.id)).where(dept.org.parent.eq(123));

在我的查询前后，其他语句修改了查询对象。这会导致错误：

O DEBUG JPAQuery - select count(distinct dossier_) from Dossier dossier_ left join dossier_.acties actie_ inner join actie_.organisatieStructuur organisatieStructuur_ on actie_.organisatieStructuur.id = organisatieStructuur_.id 其中 dossier_.deleted = ?1 和 organisatieStructuur_.ouder = ?2

org.apache.openjpa.persistence.ArgumentException："Encountered "on" 在第 64 个字符处，但应为：[",", "GROUP", "HAVING", "INNER", "JOIN"、"LEFT"、"ORDER"、"WHERE"、]。”在解析 JPQL 时“select count(distinct dossier_) 来自档案档案_ 左加入 dossier_.acties actie_ 在 actie_.organisatieStructuur.id = organisatieStructuur_.id 上内部加入 actie_.organisatieStructuur organisatieStructuur_ 其中 dossier_.deleted = ?1 和 organisatieStructuur_.ouder = ?2".

[2 月 9 日添加：] 域模型（仅显示包含字段的第一部分，其他 getter/setter 方法因大小而未显示）：

@Entity
public class Dossier extends AbstractEntity implements Serializable, HasCommunicaties {
private static final String SHAREPOINT_NR_FORMAT = "{0,number,0000}/{1,number,00}";

@Version
private long version;

private int jaar;
private int volgNummer;

private Status status;

public enum Status {
    OPEN, AFGESLOTEN;
}

@Temporal(TemporalType.TIMESTAMP)
private Date datumStatus;

@NotNull
@Column(length = 5000)
@Size(max = 5000)
private String beschrijvingVaststelling;
@Column(length = 5000)
@Size(max = 5000)
private String oorzaakVaststelling;

@ManyToOne
private ZorgDomein zorgDomein;
@ManyToOne(fetch = FetchType.LAZY)
@NotNull
private Bron bron;

@ManyToOne
private KernWaarde kernWaarde;

private String pdca;

@Valid
@OneToMany(mappedBy = "dossier", cascade = CascadeType.ALL, orphanRemoval = true)
@Size(min = 1)
private List<PlaatsVaststelling> plaatsVaststellingen = new ArrayList<PlaatsVaststelling>();

@ManyToOne(fetch = FetchType.LAZY)
private Proces proces;
@NotNull
private String beheerder;
@Temporal(TemporalType.DATE)
@Past
private Date datumVaststelling;
@ManyToOne(fetch = FetchType.LAZY)
private TypeVaststelling typeVaststelling;
@ManyToOne(fetch = FetchType.LAZY)
private Prioritering prioritering;
@ManyToOne(fetch = FetchType.LAZY)
private AuditRapport auditRapport;

@OneToMany(mappedBy = "dossier", cascade = CascadeType.ALL)
@OrderBy("volgnummer")
@Valid
private List<Actie> acties = new ArrayList<Actie>();
@OneToMany(mappedBy = "dossier")
@OrderBy("datum desc")
private List<Communicatie> communicaties = new ArrayList<Communicatie>();
@OneToMany(mappedBy = "dossier", cascade = CascadeType.ALL)
@OrderBy("datum desc")
private List<Historiek> historieks = new ArrayList<Historiek>();

private boolean vertrouwelijk;
@ElementCollection
private List<String> beheerders = new ArrayList<String>();
@ElementCollection
private List<String> lezers = new ArrayList<String>();

private boolean mailPVAVerstuurd;
private Date datumAanpakTegen;


private boolean deleted;

Answer 1

这个SQL

SELECT * FROM ACT
JOIN ORG DEPT ON ACT.ORGID = DEPT.ID
JOIN ORG DEPT2 ON DEPT.P_ID = DEPT2.ID
WHERE DEPT.P_ID = 123

可以通过

表示

QAct act = QAct.act;
QOrg dept = new QOrg("dept");
QOrg dept2 = new QOrg("dept2");
query.from(act)
     .join(act.org, dept)
     .join(dept.p, dept2)
     .where(dept2.p.id.eq(123))
     .list(act);

我不确定如何将 SQL 映射到您的领域模型，这就是我使用接近 SQL 关系的实体名称的原因。

JPAQuery (QueryDSL) 中的非致命用户错误

nonfatal user error in JPAQuery (QueryDSL)

jpa

querydsl