使用链表结构跟踪 C 程序中可能的内存泄漏

Tracking Possible Memory Leak in C program using Linked List Struct

该程序应该读取输入,直到读取到 0 或负数。然后使用下面的结构将其按升序放入链表中。

当我收到测试用例 0-3 的电子邮件时,我全部通过了。这些输入由随机数字组成,例如 1 2 3 4 5 -1 或 3493494 2922 -1.

最后一个输入文件“#### failed test”包含一个空白页,即输入 txt。所以我的程序自动说 "The linked list is empty"。但是出现内存检查错误。

这个错误是因为block吗? "free(curr);" 应该在 printf 之后吗?

  if(head == NULL)
  {
     printf("The list is empty\n");
     return(-1);
  }

我问这个是因为当程序正常运行并执行时,它到达最后一行,它释放了 curr 变量的内存。但是当列表为空时,它会立即转到 "head == NULL" 语句并在不释放变量的情况下退出。

我的教授通过电子邮件向我发送了每个输入不同的测试用例:

 #### Passed test 0.
 #### Passed test 1.
 #### Passed test 2.
 #### Passed test 3.
 #### Failed test MemoryCheck. Output of memory checker follows.
 ==23571== 128 (32 direct, 96 indirect) bytes in 2 blocks are definitely        
 lost in loss record 2 of 2
 ==23571== at 0x4A07218: malloc (vg_replace_malloc.c:296)
 ==23571== by 0x40071A: main (in /eecs/dept/course/2015-    
 16/F/2031/submit/lab7/cse13020/q2) 
 ==23571== 

代码:

#include<stdio.h>
#include<stdlib.h>


struct node
{
   int node;
   struct node* next;
};


void insert(struct node** head, struct node* node)
{
    struct node* curr;

    if (*head == NULL || (*head)->node >= node->node)
    {
       node->next = *head;
       *head = node;
    }
    else
    {
       curr = *head;

        while (curr->next!= NULL && curr->next->node < node->node)
           curr = curr->next;

        node->next = curr->next;
        curr->next = node;
    }
}


int main()
{

   struct node *head = NULL;
   struct node *curr;

   int n;

   while(1)
   {

      scanf("%d", &n);

      if(n <= 0) 
        break;

      curr = (struct node*) malloc(sizeof(struct node));
      curr->node  = n;
      curr->next =  NULL;

      insert(&head, curr); 
   }

  if(head == NULL)
  {
     printf("The list is empty\n");
     return(-1);
  }

  printf("The linked list is:\n");

  while(1)
  {
     if(head == NULL) {
       printf("NULL\n");
       break;
     }
     printf("%d-->", head->node);
     head = head->next;
  }


  free(curr);  
}

您需要释放最后一个 while 循环中的 head 节点:

while(1)
{
  if(head == NULL) {
    printf("NULL\n");
    break;
  }
  printf("%d-->", head->node);
  void *tmp = head;
  head = head->next;
  free(tmp);
}

并删除 free(curr);.

您还应该检查 scanf 是否成功,或者之前将 n 设置为某个负值。