将二维数组冒泡排序更改为计数排序

Question

以下代码使用冒泡法按第一个元素对行进行排序。我无法将其更改为计数排序。

public void SortStack(double[,] n)
{
   for (int i = 0; i < n.GetLength(0) - 1; i++)
   {
       for (int j = i; j < n.GetLength(0); j++)
       {
           if (n[i, 0] > n[j, 0]) 
           {
               for (int k = 0; k < n.GetLength(1); k++)
               {
                   var temp = n[i, k];
                   n[i, k] = n[j, k];
                   n[j, k] = temp;
               }
           }
        }
   }
}

请帮忙。

Answer 1

正如您根据每行的第一个元素进行冒泡排序一样。你也应该像那样进行计数排序。所以你只需要计算每一行的第一项。

private static int[,] CountingSort2D(int[,] arr)
{
    // find the max number by first item of each row
    int max = arr[0, 0];
    for (int i = 0; i < arr.GetLength(0); i++)
    {
        if (arr[i, 0] > max) max = arr[i, 0]; 
    }

    // we want to get count of first items of each row. thus we need 1d array.
    int[] counts = new int[max + 1]; 

    // do the counting. again on first index of each row
    for (int i = 0; i < arr.GetLength(0); i++)
    {
        counts[arr[i, 0]]++; 
    }
    for (int i = 1; i < counts.Length; i++)
    {
        counts[i] += counts[i - 1];
    }

    // result is sorted array
    int[,] result = new int[arr.GetLength(0), arr.GetLength(1)];

    for (int i = arr.GetLength(0) - 1; i >= 0; i--)
    {
        counts[arr[i, 0]]--;

        // now we need to copy columns too. thus we need another loop
        for (int j = 0; j < arr.GetLength(1); j++)
        {
            result[counts[arr[i, 0]], j] = arr[i, j];
        }
    }

    return result;
}

这是测试。

static void Main()
{
    Random rand = new Random();
    int[,] arr = new int[3,3];
    for (int i = 0; i < 3; i++)
    {
        for (int j = 0; j < 3; j++)
        {
            arr[i, j] = rand.Next(0, 100);
        }
    }

    int[,] newarr = CountingSort2D(arr);

    for (int i = 0; i < arr.GetLength(0); i++)
    {
        Console.Write("{ ");
        for (int j = 0; j < arr.GetLength(1); j++)
        {
            Console.Write(arr[i, j] + " ,");
        }
        Console.Write("} ,");
    }

    Console.WriteLine();

    for (int i = 0; i < newarr.GetLength(0); i++)
    {
        Console.Write("{ ");
        for (int j = 0; j < newarr.GetLength(1); j++)
        {
            Console.Write(newarr[i, j] + " ,");
        }
        Console.Write("} ,");
    }

    Console.WriteLine();
}

示例输出：

{ 49,66,8 },{ 33,39,64 },{ 65,52,76 } // Original array
{ 33,39,64 },{ 49,66,8 },{ 65,52,76 } // Sorted array

将二维数组冒泡排序更改为计数排序

Change 2d array bubble sort to counting sort

c#

arrays

sorting

counting-sort