C ++无限循环，返回问题

Question

void phonebookmenu() {
    phonebook ph;

    string str;

    cin.ignore();
    cout << "PH> ";
    getline(cin, str); //Input from user.

    string buf; // Have a buffer string.
    stringstream ss(str); // Insert the string into a stream.
    vector<string> tokens; // Create vector to hold the words.

    while (ss >> buf){
        tokens.push_back(buf); //Adds all the words inside the vector.
    }

    while (true){
    if (tokens[0] == "add"){
            ph.add(tokens[1],tokens[2]);
    }
    else if(tokens[0] == "lookup"){
            ph.lookup(tokens[1]);
    }
    else if(tokens[0] == "change"){
            ph.change(tokens[1],tokens[2]);
    }
    else if(tokens[0] == "alias"){
            ph.alias(tokens[1],tokens[2]);
    }
    else if(tokens[0] == "quit"){

            //Return to the "Main-menu"
    }

    else{
        cout << "Invalid input" << endl;
    }
}

所以我从 "Main-menu" 调用此菜单，但在我输入类似 "Add peter 123" 的内容后，它会执行 returns 到 "Main-menu" 的功能，我不想。它应该回到

cout << "PH> ";

所以我可以继续做手术

Answer 1

循环不围绕 cout/input/determine/do something 逻辑。仅在 determine/do something 左右。将 while 移到 cout 之前，看看会发生什么。请务必将最有帮助的答案标记为答案。

C ++无限循环，返回问题

C++ Infinite-loop, Issue with returning

c++

loops

vector

infinite