使用 spritekit 检测释放滑动 swift 时的坐标

Question

你好，如果有人能帮助我，那就太好了！

我需要获取滑动的坐标。我可以从 locationInNode 等获取初始触摸的坐标，但是我们如何获取滑动释放点的坐标？

func touchesBegan(touches: Set<UITouch>, withEvent event: UIEvent?) {
    touched = true

    for touch in touches {
        location = touch.locationInNode(self)
        print(location)
    }
}

这就是我获取初始坐标的方式，我也为 touchesMoved 这样做了

override func touchesMoved(touches: Set<UITouch>, withEvent event: UIEvent?) {
    for touch in touches {
        location = touch.locationInNode(self)
        print(location)
    }

使用此代码，它不会打印触摸时释放的最终坐标。

基本上我想用坐标来锻炼第一次触摸和释放滑动时的点之间的距离。感谢您的帮助！！

Answer 1

抓取滑动状态，从began到ended：

let point: CGPoint = recognizer.location(in: recognizer.view!)
if recognizer.state == .began {
    print(NSCoder.string(for: point))
}
else if recognizer.state == .ended {
    print(NSCoder.string(for: point))
}

Answer 2

-(IBAction)swipe:(UIGestureRecognizer*)sender
{
    UIView *view1 = sender.view;

    if (sender.state == UIGestureRecognizerStateEnded) {
           CGPoint touchUpPoint = [sender locationInView:view1];
        NSLog(@"x=%f, y=%f",touchUpPoint.x,touchUpPoint.y);
    }

}

使用 spritekit 检测释放滑动 swift 时的坐标

Detect coordinates on release of a swipe swift with spritekit

ios

swift

sprite-kit

uigesturerecognizer

swipe-gesture