如何镜像下面给出的曲线？

Question

我不知道哪个是正确的功能，（例如flipud、fliplr）但我希望镜像如下所示的曲线：到

一个

但是I和V值如下：

I=
7.533307359
7.525186507
7.519095869
7.506914591
7.486612462
7.486612462
7.482552036
7.480521823
7.47849161
7.474431184
7.470370759
7.46428012
7.462249907
7.452098842
7.433826926
7.389162242
7.309983939
7.167869035
6.930334125
6.581137504
6.116218748
5.570091475
4.983359945
4.398658627
3.838319864
3.32670621
2.873968732
2.476047001
2.126850381
1.838560148
1.590874173
1.377701817
1.203103507
1.054897965
0.926994552
0.819393267
0.726003473
0.650885596
0.585918783
0.529072821
0.480347711
0.435683027
0.397108982
0.366655789
0.334172382
0.305749401
0.285447272
0.26311493
0.244843014
0.226571098
0.210329394
0.196117904
0.181906414
0.171755349
0.163634498
0.15145322
0.145362581
0.139271943
0.131151091
0.125060452
0.118969814
0.114909388
0.110848962
0.104758323
0.100697897
0.098667684
0.092577046
0.090546833
0.08851662
0.086486407
0.082425981
0.078365555
0.076335342
0.07430513
0.072274917
0.068214491
0.066184278
0.064154065
0.062123852
0.058063426
0.047912362
0.047912362
0.045882149
0.047912362
0.047912362
0.045882149
0.045882149
0.047912362
0.047912362
0.045882149
0.045882149
0.045882149
0.045882149
0.045882149
0.047912362
0.043851936
0.047912362
0.045882149
0.047912362
0.045882149

和

V=
0.599996469
2.099894456
3.569210247
5.00782203
6.446312
7.915719151
9.385065396
10.7932168
12.23198084
13.64010179
15.10944804
16.48692588
17.95630258
19.36433216
20.77223994
22.17975182
23.5255207
24.80912023
26.06067582
27.18810588
28.09951157
28.97908648
29.70498908
30.30847154
30.88170679
31.30260967
31.57133245
31.87149012
32.11115336
32.2905049
32.43985285
32.65094381
32.67893749
32.76855235
32.85847175
32.91808302
32.97790748
33.06861865
33.06764415
33.15862941
33.12728588
33.18784121
33.1872626
33.21741845
33.2169312
33.27773015
33.27742562
33.30770329
33.30742921
33.30715513
33.3069115
33.33731098
33.30648516
33.30633289
33.30621108
33.36725366
33.33654965
33.30584564
33.33633648
33.33624512
33.39737906
33.33609285
33.36664459
33.36655323
33.39710498
33.39707452
33.36637052
33.39695271
33.39692226
33.36627916
33.36621825
33.36615734
33.36612689
33.36609644
33.36606598
33.39661773
33.36597462
33.39655682
33.36591372
33.39646546
33.36570055
33.39631319
33.36567009
33.36570055
33.39631319
33.39628274
33.39628274
33.39631319
33.39631319
33.42689539
33.39628274
33.39628274
33.39628274
33.39628274
33.39631319
33.45747759
33.39631319
33.39628274
33.39631319
33.39628274

I 和 V 的 100x1 数组

Answer 1

您在问题中给出了答案：只需使用fliplr函数即可！您需要使用：

V1 = max(V) - fliplr(V)
I1 = fliplr(I)
plot(V1,I1);

唯一重要的是——镜像很容易获取，但是什么时候需要定位呢？（看看我的黄色和蓝色曲线）。

这部分 max(V) 定义了 x 轴的曲线移动。这意味着如果你像你一样使用它，新曲线从 0（红色曲线）开始。如果您需要移动它，请使用 max(V) + 1 等

如何镜像下面给出的曲线？

How do I mirror the curve given below?

matlab

rotation

flip

mirror