swift spritekit：如何停止运行块？

Question

如何停止来自运行区块的所有操作：

func slideShowControl () {


    let noObject = SKSpriteNode()
    noObject.name = "noObject"

    addChild(noObject)



    let block = SKAction.runBlock({

        self.slideShow(1)
        print("slide01")

        self.runAction(SKAction.waitForDuration(5), completion: {

            print("slide02")


        })

        self.runAction(SKAction.waitForDuration(8), completion: {

            print("slide03")

        })

        ...

        self.runAction(SKAction.waitForDuration(17), completion: {

            print("slide06")

        })

    })


    noObject.runAction(block, withKey: "stop")

self.slideShow(1) 只是呈现一个发送密钥 "stop" 的按钮，但块继续运行并打印。可以停止这个块吗？

noObject.removeActionForKey("stop")

Answer 1

So you are naming an object "noObject" and an action "stop"? :)

无论如何，您应该使用 group 和一些 sequence 操作。

想法

这个代码

self.runAction(SKAction.waitForDuration(5), completion: {
    print("slide02")
})

也可以这样写

let action1 = SKAction.sequence([SKAction.waitForDuration(5), SKAction.runBlock { print("slide02") }])

解决方案

给定一个精灵

let sprite = SKSpriteNode()

和 4 个动作

let action0 = SKAction.runBlock { print("slide01") }
let action1 = SKAction.sequence([SKAction.waitForDuration(5), SKAction.runBlock { print("slide02") }])
let action2 = SKAction.sequence([SKAction.waitForDuration(8), SKAction.runBlock { print("slide03") }])
let action3 = SKAction.sequence([SKAction.waitForDuration(6), SKAction.runBlock { print("slide06") }])

我们可以像这样对动作进行分组

let group = SKAction.group([action0, action1, action2, action3])

现在我们可以运行按键操作

sprite.runAction(group, withKey: "group")

并停止它

sprite.removeActionForKey("group")

swift spritekit：如何停止运行块？

swift spritekit : How to stop a runBlock?

removeall

sprite-kit

swift

想法

解决方案