如何在生成的 spritekit 节点上设置 physicsBody

Question

我的物理体有问题。我有大约 20 个随机生成的节点可供查看。每次节点生成时，我都会设置对象的物理特性，如下所示：

func showObject(){
    let texture =  SKTexture(imageNamed: "A.png")
    object = SKSpriteNode(texture: texture)
        object.name = "A"
    object.position = CGPoint(x: 0, y: self.frame.width)
    object.setScale(0.7)
    object.zPosition = 2
    object.run(moveAndRemove)

    object.physicsBody = SKPhysicsBody(texture: texture, size: texture.size())
    object.physicsBody?.categoryBitMask = PhysicsCategory.Object
    object.physicsBody?.collisionBitMask = PhysicsCategory.Object2
    object.physicsBody?.contactTestBitMask = PhysicsCategory.Object2
    object.physicsBody?.affectedByGravity = false
    object.physicsBody?.isDynamic = true

    addChild(object)
}

我认为这不是最优的，因为每次生成节点时都会设置 physicsBody。因此，我有时会出现轻微的闪烁 - 当应用运行时 fps 较低。 physicsBody什么时候关闭，一切正常。所以我有一个简单的问题。如何在游戏开始后为所有 20 个节点设置物理体，而不是仅仅生成它们而不再次创建 physicsBody。我尝试将带有纹理的物理体直接设置为 SKView 但在此之后，应用程序崩溃并出现 nil 错误。

感谢您的提示。

有我的出生点：

let SpawnObject = SKAction.run({
    () in

    let randomFunc = [self.showObject, self.showObject1.......]
        let randomResult = Int(arc4random_uniform(UInt32(randomFunc.count)))
        randomFunc[randomResult]()
})

let delay1 = SKAction.wait(forDuration: 0.9)
let SpawnDelay1 = SKAction.sequence([SpawnObject,delay1])
let SpawnDelayForever1 = SKAction.repeatForever(SpawnDelay1)
self.run(SpawnDelayForever1)

let distance = CGFloat(self.frame.height + 200)
let moveObject = SKAction.moveBy(x: -distance, y: 0, duration: TimeInterval(0.004 * distance))
let removeObject = SKAction.removeFromParent()
moveAndRemove = SKAction.sequence([moveObject,removeObject])

Answer 1

有很多不同的方法可以解决这个问题，如果我生成多个相同的对象，我喜欢做的是将对象预加载到一个数组中，然后根据需要从数组中拉出它们，当你已经完成了你可以从场景中删除它们但将它们保留在数组中的对象。然后您可以再次使用该对象，而不必重新创建它，也不必重新创建导致延迟的物理体

private var moveAndRemove = SKAction()
private var objects = [SKSpriteNode]()
private let objectCount = 20

override func didMove(to view: SKView) {

    for x in 0..<objectCount {
        let texture =  SKTexture(imageNamed: "A")
        let object = SKSpriteNode(texture: texture)
        object.name = "A"
        object.isHidden = true
        object.setScale(0.7)
        object.zPosition = 2

        object.physicsBody = SKPhysicsBody(texture: texture, size: texture.size())
        object.physicsBody?.categoryBitMask = 0
        object.physicsBody?.collisionBitMask = 0
        object.physicsBody?.contactTestBitMask = 0
        object.physicsBody?.affectedByGravity = false
        object.physicsBody?.isDynamic = true

        objects.append(object)
    }

    let distance = CGFloat(self.frame.height + 200)
    let moveObject = SKAction.moveBy(x:0 - distance, y: 0, duration: Double(0.004 * distance))
    let removeObject = SKAction.removeFromParent()
    let hideObject = SKAction.hide()
    moveAndRemove = SKAction.sequence([moveObject, hideObject, removeObject])

    let SpawnObject = SKAction.run( {

        let randomResult = Int(arc4random_uniform(UInt32(self.objects.count)))
        self.showObject(objectIndex: randomResult)
    })

    let delay1 = SKAction.wait(forDuration: 0.9)
    let SpawnDelay1 = SKAction.sequence([SpawnObject, delay1])
    let SpawnDelayForever1 = SKAction.repeatForever(SpawnDelay1)
    self.run(SpawnDelayForever1)
}

func showObject(objectIndex: Int) {

    let object = objects[objectIndex]

    guard object.isHidden == true else { return }

    object.isHidden = false
    object.position = CGPoint(x: 0, y: self.frame.width)
    object.zPosition = 10000
    addChild(object)
    object.run(moveAndRemove)
}

我已经编辑了答案以反映您的生成代码。请注意，我只是通过检查对象的隐藏状态来检查数组中的对象是否已被使用。还有许多其他方法可以检查对象是否已被使用，但您必须找出最适合您的方法。

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