如何制作一个在 update() 中按下按钮时启动的 int 秒计数器?
How can I make an int second counter that starts when a button is pressed in update()?
我正在尝试制作第二个在 GameScene.update() 中运行的计数器,当我按下一个按钮最多 5 秒时计数,然后停止并重置为 0 等待另一个按钮按下。
这是我的如果按钮被按下的代码:
override func update(currentTime: CFTimeInterval) {
if (Data.gameScene.buttonPressed == true) {
player.texture = SKTexture(imageNamed: "Spaceship2")
player.physicsBody = nil
}
}
如您所见,当按下按钮时,玩家会消失(Spaceship2 的不透明度较低)并且它不再具有物理体(因此敌人无法击中它)。
我想要的是这个(伪代码):
if (button pressed == true) {
start timer
if timer < 5 seconds {
player can't be hit and is invisible
} else {
player can be hit and is visible
}
}
有人能帮我吗?
只需设置一个在 5 秒后触发的计时器:
class MyViewController: UIViewController {
var timer: NStimer?
var timerIsRunning = false
func buttonPressed() {
if timerIsRunning {
return
}
// start the timer
self.timer = NSTimer.scheduledTimerWithTimeInterval(5, target: self, selector: "update", userInfo: nil, repeats: false)
self.timerIsRunning = true
player.texture = SKTexture(imageNamed: "Spaceship2")
player.physicsBody = nil
}
func update() {
self.timer?.invalidate()
self.timerIsRunning = false
...
}
}
希望你明白了。
由于定期调用 update
函数,并且方便地提供时间戳(以秒为单位),您可以简单地在按下按钮时保存时间戳,并使用它来确定何时5秒结束。
override func update(currentTime: CFTimeInterval) {
if (Data.gameScene.buttonPressed == true) {
player.texture = SKTexture(imageNamed: "Spaceship2")
player.physicsBody = nil
player.isInvisible = true
player.startInvisible = currentTime
}
else if (player.isInvisible){
if (currentTime - player.startInvisible > 5) {
player.isInvisible = false
player.texture = ...
player.physicsBody = ...
}
}
}
您可以通过一系列等待操作和运行块操作来完成此操作。
override func update(currentTime: CFTimeInterval) {
if (Data.gameScene.buttonPressed == true) {
//put code to make the player invisible
let waitAction = SKAction.waitForDuration(5)
let makePlayerVisibleAction = SKAction.runBlock {
//put code to make the player visible
}
let action = SKAction.sequence([waitAction, makePlayerVisibleAction])
player.runAction(action)
}
}
我正在尝试制作第二个在 GameScene.update() 中运行的计数器,当我按下一个按钮最多 5 秒时计数,然后停止并重置为 0 等待另一个按钮按下。
这是我的如果按钮被按下的代码:
override func update(currentTime: CFTimeInterval) {
if (Data.gameScene.buttonPressed == true) {
player.texture = SKTexture(imageNamed: "Spaceship2")
player.physicsBody = nil
}
}
如您所见,当按下按钮时,玩家会消失(Spaceship2 的不透明度较低)并且它不再具有物理体(因此敌人无法击中它)。
我想要的是这个(伪代码):
if (button pressed == true) {
start timer
if timer < 5 seconds {
player can't be hit and is invisible
} else {
player can be hit and is visible
}
}
有人能帮我吗?
只需设置一个在 5 秒后触发的计时器:
class MyViewController: UIViewController {
var timer: NStimer?
var timerIsRunning = false
func buttonPressed() {
if timerIsRunning {
return
}
// start the timer
self.timer = NSTimer.scheduledTimerWithTimeInterval(5, target: self, selector: "update", userInfo: nil, repeats: false)
self.timerIsRunning = true
player.texture = SKTexture(imageNamed: "Spaceship2")
player.physicsBody = nil
}
func update() {
self.timer?.invalidate()
self.timerIsRunning = false
...
}
}
希望你明白了。
由于定期调用 update
函数,并且方便地提供时间戳(以秒为单位),您可以简单地在按下按钮时保存时间戳,并使用它来确定何时5秒结束。
override func update(currentTime: CFTimeInterval) {
if (Data.gameScene.buttonPressed == true) {
player.texture = SKTexture(imageNamed: "Spaceship2")
player.physicsBody = nil
player.isInvisible = true
player.startInvisible = currentTime
}
else if (player.isInvisible){
if (currentTime - player.startInvisible > 5) {
player.isInvisible = false
player.texture = ...
player.physicsBody = ...
}
}
}
您可以通过一系列等待操作和运行块操作来完成此操作。
override func update(currentTime: CFTimeInterval) {
if (Data.gameScene.buttonPressed == true) {
//put code to make the player invisible
let waitAction = SKAction.waitForDuration(5)
let makePlayerVisibleAction = SKAction.runBlock {
//put code to make the player visible
}
let action = SKAction.sequence([waitAction, makePlayerVisibleAction])
player.runAction(action)
}
}