swift plist 解码器全局 Spritekit

Question

我想要我的 plist 中的字典，我可以在整个游戏场景中使用它。但是在我的解决方案中，我总是必须调用 parseConfig 函数才能从 plist 中获取字典。

struct Config: Decodable {
    private enum CodingKeys: String, CodingKey {
        case zPositions, enemy, player
    }

    let zPositions: [String:Double]
    let enemy: [String:[String:Double]]
    let player: [String:[String:Double]]
}

func parseConfig() -> Config {
    let url = Bundle.main.url(forResource: "Config", withExtension: "plist")!
    let data = try! Data(contentsOf: url)
    let decoder = PropertyListDecoder()
    return try! decoder.decode(Config.self, from: data)
}

Answer 1

你可以尝试写一个只加载一次的闭包

lazy var myConfig : Config  = {  
      let url = Bundle.main.url(forResource: "Config", withExtension: "plist")!
      let data = try! Data(contentsOf: url)
      let decoder = PropertyListDecoder()
      return try! decoder.decode(Config.self, from: data)
}()

或在所有应用程序中的单例中

class Service {

 static let shared = Service()

  lazy var myConfig : Config  = { 

      let url = Bundle.main.url(forResource: "Config", withExtension: "plist")!
      let data = try! Data(contentsOf: url)
      let decoder = PropertyListDecoder()
      return try! decoder.decode(Config.self, from: data)
  }()

}

Answer 2

尝试 crate lazy 属性.

类似于：- 如果使用 gloabaly

var parsedConfig: Config  = {
    let url = Bundle.main.url(forResource: "Config", withExtension: "plist")!
    let data = try! Data(contentsOf: url)
    let decoder = PropertyListDecoder()
    return try! decoder.decode(Config.self, from: data)
}()

if in class 在 var

之前添加 lazy

swift plist 解码器全局 Spritekit

swift plist decoder global Spritekit

ios

swift

sprite-kit

plist