vhdl 和门返回未知值
vhdl and gate returning unknown value
我正在实现一个多路复用器,但门无故返回“x”,请帮忙。
正如您在屏幕截图中看到的,结果刚刚从“1”变成了“x”。
我为和门做了一个测试台,它自己工作得很好。
它应该是一个 3 位 4:1 多路复用器。
this is the problem
这是源代码,我正在使用 ghdl。
LIBRARY IEEE;
USE IEEE.std_logic_1164.ALL;
ENTITY mux41 IS
PORT (
i1 : IN std_logic_vector(2 DOWNTO 0);
i2 : IN std_logic_vector(2 DOWNTO 0);
i3 : IN std_logic_vector(2 DOWNTO 0);
i4 : IN std_logic_vector(2 DOWNTO 0);
sel : IN std_logic_vector(1 DOWNTO 0);
y : OUT std_logic_vector(2 DOWNTO 0)
);
END mux41;
ARCHITECTURE rtl OF mux41 IS
COMPONENT andgate
PORT (
input1 : IN std_logic;
input2 : IN std_logic;
input3 : IN std_logic;
and_output : OUT std_logic
);
END COMPONENT;
COMPONENT orgate
PORT (
input1 : IN std_logic;
input2 : IN std_logic;
input3 : IN std_logic;
input4 : IN std_logic;
or_output : OUT std_logic
);
END COMPONENT;
signal not_sel : std_logic_vector(1 DOWNTO 0);
signal and_result : std_logic_vector(3 DOWNTO 0);
signal or_result : std_logic_vector(2 DOWNTO 0);
BEGIN
not_sel <= not sel;
and_gate_assignment : for i in 0 to 2 generate
and_output1: andgate port map(input1=>i1(i), input2=>not_sel(1), input3=>not_sel(0), and_output=>and_result(0));
and_output2: andgate port map(input1=>i2(i), input2=>not_sel(1), input3=>sel(0), and_output=>and_result(1));
and_output3: andgate port map(input1=>i3(i), input2=>sel(1), input3=>not_sel(0), and_output=>and_result(2));
and_output4: andgate port map(input1=>i4(i), input2=>sel(1), input3=>sel(0), and_output=>and_result(3));
or_output: orgate port map(input1=>and_result(0), input2=>and_result(1), input3=>and_result(2), input4=>and_result(3), or_output=>or_result(i));
end generate and_gate_assignment;
y <= or_result;
END rtl;
这里是和门;
library ieee;
use ieee.std_logic_1164.all;
entity andgate is
port (
input1 : in std_logic;
input2 : in std_logic;
input3 : in std_logic;
and_output : out std_logic
);
end andgate;
architecture rtl of andgate is
signal and1 : std_logic;
signal and2 : std_logic;
begin
and1 <= input1 and input2;
and2 <= and1 and input3;
and_output <= and2;
end rtl;
这真的没什么,这可能是时间问题吗?
添加 orgate 的实体和架构
use ieee.std_logic_1164.all;
entity orgate is
port (
input1: in std_logic;
input2: in std_logic;
input3: in std_logic;
input4: in std_logic;
or_output: out std_logic
);
end entity;
architecture foo of orgate is
begin
or_output <= input1 or input2 or input3 or input4;
end architecture;
和一个测试平台
library ieee;
use ieee.std_logic_1164.all;
use ieee.numeric_std.all;
entity mux41_tb is
end entity;
architecture foo of mux41_tb is
signal i1: std_logic_vector(2 downto 0);
signal i2: std_logic_vector(2 downto 0);
signal i3: std_logic_vector(2 downto 0);
signal i4: std_logic_vector(2 downto 0);
signal sel: std_logic_vector(1 downto 0);
signal y: std_logic_vector(2 downto 0);
begin
DUT:
entity work.mux41
port map (
i1 => i1,
i2 => i2,
i3 => i3,
i4 => i4,
sel => sel,
y => y
);
STIMULI:
process
begin
for i in 0 to 7 loop
i1 <= std_logic_vector(to_unsigned(i, 3));
for j in 0 to 7 loop
i2 <= std_logic_vector(to_unsigned(j, 3));
for k in 0 to 7 loop
i3 <= std_logic_vector(to_unsigned(k, 3));
for m in 0 to 7 loop
i4 <= std_logic_vector(to_unsigned(m, 3));
for n in 0 to 3 loop
sel <= std_logic_vector(to_unsigned(n,2));
wait for 10 ns;
end loop;
end loop;
end loop;
end loop;
end loop;
wait;
end process;
end architecture;
允许您的读者复制您的问题。
添加更多信号可能有助于理解问题:
'X'来自驱动程序冲突。这里有多个驱动程序连接到生成的块中的 and_result(3 downto 0)。当所有驱动器都为“0”时,信号被解析为“0”。当发生冲突时,会出现 'X'.
解决方案是将 and_result 声明移动到生成语句块声明区域(使用以下 begin 将声明与语句分开):
signal not_sel : std_logic_vector(1 DOWNTO 0);
-- signal and_result : std_logic_vector(3 DOWNTO 0); -- MOVE FROM HERE
signal or_result : std_logic_vector(2 DOWNTO 0);
BEGIN
not_sel <= not sel;
and_gate_assignment : for i in 0 to 2 generate
signal and_result : std_logic_vector(3 DOWNTO 0); -- TO HERE
BEGIN -- AND ADD A FOLLOWING BEGIN
and_output1: andgate port map(input1=>i1(i), input2=>not_sel(1), input3=>not_sel(0), and_output=>and_result(0));
这给了你
预期的结果。
generate 语句表示零个或多个详细说明中的块语句。这里的三个块语句中的每一个都包含一个用于切片的 std_logic 元素的 4 到 1 多路复用器。
一个单独的多路复用器具有将四个与门实例中的每一个的输出连接到一个有机门实例的信号网络。通过依赖 and_result
的共同声明,您已经将所有三个块的 andgate 输出短路在一起。
将 and_result
声明移动到生成语句块声明区域会导致为每个生成的块语句复制它。因为块语句是一个声明性区域,所以 and_result
的三个声明在每个生成的块之外是不可见的,因为范围和可见性规则匹配它们是分层框图中每个块的本地 - 三个 and_result
元素不再连接到所有三个块。这消除了多个驱动程序。
我正在实现一个多路复用器,但门无故返回“x”,请帮忙。 正如您在屏幕截图中看到的,结果刚刚从“1”变成了“x”。 我为和门做了一个测试台,它自己工作得很好。 它应该是一个 3 位 4:1 多路复用器。 this is the problem
这是源代码,我正在使用 ghdl。
LIBRARY IEEE;
USE IEEE.std_logic_1164.ALL;
ENTITY mux41 IS
PORT (
i1 : IN std_logic_vector(2 DOWNTO 0);
i2 : IN std_logic_vector(2 DOWNTO 0);
i3 : IN std_logic_vector(2 DOWNTO 0);
i4 : IN std_logic_vector(2 DOWNTO 0);
sel : IN std_logic_vector(1 DOWNTO 0);
y : OUT std_logic_vector(2 DOWNTO 0)
);
END mux41;
ARCHITECTURE rtl OF mux41 IS
COMPONENT andgate
PORT (
input1 : IN std_logic;
input2 : IN std_logic;
input3 : IN std_logic;
and_output : OUT std_logic
);
END COMPONENT;
COMPONENT orgate
PORT (
input1 : IN std_logic;
input2 : IN std_logic;
input3 : IN std_logic;
input4 : IN std_logic;
or_output : OUT std_logic
);
END COMPONENT;
signal not_sel : std_logic_vector(1 DOWNTO 0);
signal and_result : std_logic_vector(3 DOWNTO 0);
signal or_result : std_logic_vector(2 DOWNTO 0);
BEGIN
not_sel <= not sel;
and_gate_assignment : for i in 0 to 2 generate
and_output1: andgate port map(input1=>i1(i), input2=>not_sel(1), input3=>not_sel(0), and_output=>and_result(0));
and_output2: andgate port map(input1=>i2(i), input2=>not_sel(1), input3=>sel(0), and_output=>and_result(1));
and_output3: andgate port map(input1=>i3(i), input2=>sel(1), input3=>not_sel(0), and_output=>and_result(2));
and_output4: andgate port map(input1=>i4(i), input2=>sel(1), input3=>sel(0), and_output=>and_result(3));
or_output: orgate port map(input1=>and_result(0), input2=>and_result(1), input3=>and_result(2), input4=>and_result(3), or_output=>or_result(i));
end generate and_gate_assignment;
y <= or_result;
END rtl;
这里是和门;
library ieee;
use ieee.std_logic_1164.all;
entity andgate is
port (
input1 : in std_logic;
input2 : in std_logic;
input3 : in std_logic;
and_output : out std_logic
);
end andgate;
architecture rtl of andgate is
signal and1 : std_logic;
signal and2 : std_logic;
begin
and1 <= input1 and input2;
and2 <= and1 and input3;
and_output <= and2;
end rtl;
这真的没什么,这可能是时间问题吗?
添加 orgate 的实体和架构
use ieee.std_logic_1164.all;
entity orgate is
port (
input1: in std_logic;
input2: in std_logic;
input3: in std_logic;
input4: in std_logic;
or_output: out std_logic
);
end entity;
architecture foo of orgate is
begin
or_output <= input1 or input2 or input3 or input4;
end architecture;
和一个测试平台
library ieee;
use ieee.std_logic_1164.all;
use ieee.numeric_std.all;
entity mux41_tb is
end entity;
architecture foo of mux41_tb is
signal i1: std_logic_vector(2 downto 0);
signal i2: std_logic_vector(2 downto 0);
signal i3: std_logic_vector(2 downto 0);
signal i4: std_logic_vector(2 downto 0);
signal sel: std_logic_vector(1 downto 0);
signal y: std_logic_vector(2 downto 0);
begin
DUT:
entity work.mux41
port map (
i1 => i1,
i2 => i2,
i3 => i3,
i4 => i4,
sel => sel,
y => y
);
STIMULI:
process
begin
for i in 0 to 7 loop
i1 <= std_logic_vector(to_unsigned(i, 3));
for j in 0 to 7 loop
i2 <= std_logic_vector(to_unsigned(j, 3));
for k in 0 to 7 loop
i3 <= std_logic_vector(to_unsigned(k, 3));
for m in 0 to 7 loop
i4 <= std_logic_vector(to_unsigned(m, 3));
for n in 0 to 3 loop
sel <= std_logic_vector(to_unsigned(n,2));
wait for 10 ns;
end loop;
end loop;
end loop;
end loop;
end loop;
wait;
end process;
end architecture;
允许您的读者复制您的问题。 添加更多信号可能有助于理解问题:
'X'来自驱动程序冲突。这里有多个驱动程序连接到生成的块中的 and_result(3 downto 0)。当所有驱动器都为“0”时,信号被解析为“0”。当发生冲突时,会出现 'X'.
解决方案是将 and_result 声明移动到生成语句块声明区域(使用以下 begin 将声明与语句分开):
signal not_sel : std_logic_vector(1 DOWNTO 0);
-- signal and_result : std_logic_vector(3 DOWNTO 0); -- MOVE FROM HERE
signal or_result : std_logic_vector(2 DOWNTO 0);
BEGIN
not_sel <= not sel;
and_gate_assignment : for i in 0 to 2 generate
signal and_result : std_logic_vector(3 DOWNTO 0); -- TO HERE
BEGIN -- AND ADD A FOLLOWING BEGIN
and_output1: andgate port map(input1=>i1(i), input2=>not_sel(1), input3=>not_sel(0), and_output=>and_result(0));
这给了你
预期的结果。
generate 语句表示零个或多个详细说明中的块语句。这里的三个块语句中的每一个都包含一个用于切片的 std_logic 元素的 4 到 1 多路复用器。
一个单独的多路复用器具有将四个与门实例中的每一个的输出连接到一个有机门实例的信号网络。通过依赖 and_result
的共同声明,您已经将所有三个块的 andgate 输出短路在一起。
将 and_result
声明移动到生成语句块声明区域会导致为每个生成的块语句复制它。因为块语句是一个声明性区域,所以 and_result
的三个声明在每个生成的块之外是不可见的,因为范围和可见性规则匹配它们是分层框图中每个块的本地 - 三个 and_result
元素不再连接到所有三个块。这消除了多个驱动程序。