Swift 使 sksprite 节点随时间移动得更快

Question

我有一个通过函数生成的精灵节点：

    let NBrick1 = SKSpriteNode(texture: Brick1)
    NBrick1.setScale(0.04)
    NBrick1.position = CGPointMake(0.0, CGFloat(y1 + bounds/2))
    NBrick1.physicsBody = SKPhysicsBody(rectangleOfSize: NBrick1.size)
    NBrick1.physicsBody?.dynamic = true
    BrickPairs.addChild(NBrick1)

我正在使用这个 SKAction 来移动积木：

   let moveBricks = SKAction.moveByX(-distanceToMove, y: 0.0, duration: NSTimeInterval(0.01 * distanceToMove))
   let removeBricks = SKAction.removeFromParent()
   BricksMoveAndRemove = SKAction.sequence([moveBricks,removeBricks])

我想知道是否有办法让砖块随着时间的推移移动得更快。

Answer 1

其实很简单，你不需要参与SKActions。下面的代码将加速一个精灵或多个精灵的移动，（如果你应用相同的代码。）它所做的是每次将精灵的位置在每一帧中改变一点点。这是 moveFactor 变量。要更改它加速的启动速度和速率，请更改我输入的值。

var moveFactor:CGFloat = 0.5

override func update(currentTime: CFTimeInterval) {
    /* Called before each frame is rendered */
    sprite.position = CGPoint(x: sprite.position.x + moveFactor, y: sprite.position.y)
    moveFactor *= 1.005
}

Swift 使 sksprite 节点随时间移动得更快

Swift making sksprite node move faster with time

sprite-kit

skaction

skspritenode

swift